SQLSTATE [42601]：语法错误：7错误：子查询必须仅返回一列使用函数

Question

我收到错误消息“子查询必须仅返回一列”，但是当我选择curProd时，我尝试使用其他方法返回第一条记录。

我正在使用此功能，但据我所知我得到了错误：

curProd := (
        SELECT "KeysForSale".*
        FROM "KeysForSale"
        WHERE row_STab.product_id = "KeysForSale".product_id AND (("KeysForSale".begin_date < payment_date AND "KeysForSale".end_date > payment_date) OR ("KeysForSale".discounted_price IS NULL))
        ORDER BY "KeysForSale".discounted_price ASC NULLS LAST
        LIMIT 1
    );

全部功能是：

CREATE FUNCTION "paymentRun"(buyer_id integer, payment_date DATE, payMethod paymentMethod, paid_amount double precision, payDetails text) RETURNS VOID AS
$$
DECLARE
row_STab "SearchTable"%rowtype;
curProd  "KeysForSale"%rowtype;
totalPrice double precision;
returnedPID integer;
BEGIN

--For each entry in the search table
FOR row_STab IN 
(
    SELECT *
    FROM "SearchTable"
)
LOOP

    --We retrieve the associated product info, together with an available key
    curProd := (
        SELECT "KeysForSale".*
        FROM "KeysForSale"
        WHERE row_STab.product_id = "KeysForSale".product_id AND (("KeysForSale".begin_date < payment_date AND "KeysForSale".end_date > payment_date) OR ("KeysForSale".discounted_price IS NULL))
        ORDER BY "KeysForSale".discounted_price ASC NULLS LAST
        LIMIT 1
    );

    --Either there is no such product, or no keys for it
    IF curProd IS NULL THEN
        RAISE EXCEPTION 'Product is not available for purchase.';
    END IF;

    --Product's seller is the buyer - we can't let that pass
    IF curProd.user_id = buyer_id THEN
        RAISE EXCEPTION 'A Seller cannot purchase their own product.';
    END IF;

    --Fill in the rest of the data to prepare the purchase
    UPDATE "SearchTable"
    SET "SearchTable".price = (
        CASE curProd.discounted_price IS NOT NULL -- if there was a discounted price, use it
        WHEN TRUE THEN curProd.discounted_price
        ELSE curProd.price
        END
        ), "SearchTable".sk_id = curProd.sk_id 
    WHERE "SearchTable".product_id = curProd.product_id;

END LOOP;

--Get total cost
totalPrice := (
    SELECT SUM("SearchTable".price)
    FROM "SearchTable"
);

--The given price does not match the actual cost?
IF totalPrice <> paid_amount THEN
        RAISE EXCEPTION 'Payment does not match cost!';
END IF;

--Create a purchase while keeping it's ID for register
INSERT INTO "Purchases" (purchase_id, final_price, user_id, paid_date, payment_method, details)
VALUES (DEFAULT, totalPrice, buyer_id, payment_date, payMethod, payDetails)
RETURNING purchase_id INTO returnedPID;

--For each product we wish to purchase
FOR row_STab IN 
(
    SELECT *
    FROM "SearchTable"
)
LOOP

    INSERT INTO "PurchasedKeys"(sk_id, purchase_id, price)
    VALUES (row_STab.sk_id, returnedPID, row_STab.price);

    UPDATE "SerialKeys"
    SET "SerialKeys".user_id = buyer_id
    WHERE row_STab.sk_id = "SerialKeys".sk_id;

END LOOP;



END
$$
LANGUAGE 'plpgsql' ;

先感谢您

Answer 1

由于问题的答案不正确，因此我提供的是评论以外的答案。 您想要的代码是：

curProd := (
    SELECT "KeysForSale"
    FROM "KeysForSale"
    WHERE row_STab.product_id = "KeysForSale".product_id AND (("KeysForSale".begin_date < payment_date AND "KeysForSale".end_date > payment_date) OR ("KeysForSale".discounted_price IS NULL))
    ORDER BY "KeysForSale".discounted_price ASC NULLS LAST
    LIMIT 1
);

区别在于缺少.* 。 您的版本返回了一堆列-这是您遇到的错误。 您想返回一条记录 。 表名提供了这一点。

我还认为括号将具有相同的效果：

    SELECT ("KeysForSale".*)

Answer 2

对于这种情况，您不应使用语法：

var := (SELECT ..).

首选应该是SELECT INTO ：

SELECT * INTO curProd FROM ...

语法SELECT tabname FROM tabname是PostgreSQL的专有技术，尽管它很好用，但最好不要使用，因为如果没有更深的PostgreSQL知识，所有人都将无法阅读。

因为PL / pgSQL不区分大小写，所以不建议使用驼峰式（最好使用蛇形）。

如果可能，请不要使用ISAM样式：

FOR _id IN
  SELECT id FROM tab1
LOOP
  SELECT * INTO r FROM tab2 WHERE tab2.id = _id

它比加入慢得多（需要更多迭代）

FOR r IN
  SELECT tab2.*
    FROM tab1 JOIN tab2 ON tab1.id = tab2.id
LOOP
  ..

周期不利于性能。 这部分并不是很好：

FOR row_STab IN 
(
    SELECT *
    FROM "SearchTable"
)
LOOP

    INSERT INTO "PurchasedKeys"(sk_id, purchase_id, price)
    VALUES (row_STab.sk_id, returnedPID, row_STab.price);

    UPDATE "SerialKeys"
    SET "SerialKeys".user_id = buyer_id
    WHERE row_STab.sk_id = "SerialKeys".sk_id;

END LOOP;

可能的解决方案：

请使用批量命令：

INSERT INTO "PurchasedKeys"(sk_id, purchase_id, price)
   SELECT sk_id, returnedPID, price
     FROM "SearchTable"; -- using case sensitive identifiers is way to hell

UPDATE "SerialKeys"
  SET "SerialKeys".user_id = buyer_id
  FROM "SearchTable"
  WHERE "SearchTable".sk_id = "SerialKeys".sk_id;

ISAM样式的性能较低取决于迭代次数。 对于低迭代，这并不重要，对于高迭代，则是死亡。