更改JSON对象键的值，还更改其他值

Question

描述 ：已将JSON对象定义为全局变量。 var JSON_OBJECT = [];

[
{
    "user_id": "123",
    "AF": [
        {
            "formula_type": 0,
            "lag": 0
        }
    ],
    "Trend": [
        {
            "is_active": 0
        }
    ]
},
{
    "user_id": "859",
    "AF": [
        {
            "formula_type": 0,
            "lag": 0
        }
    ],
    "Trend": [
        {
            "is_active": 0
        }
    ]
}
]

JSON对象(JSON_OBJECT)由以下函数构造： jsonCreator

function jsonCreator() {

var af_Array = [];
var Trend_Array = [];
var selectedUsers = ['123','859','235']

for (var i = 0; i < 1; i++) {
    var af_keys = {}
    af_keys.formula_type = i;
    af_keys.lag = i;
    af_Array.push(af_keys);
}

for (var j = 0; j < 1; j++) {
    var trends_keys = {}
    trends_keys.is_active = j;
    Trend_Array.push(trends_keys);
}


for (var indexUsers = 0; indexUsers < selectedUsers.length; indexUsers++) {
    var jsonObj = {};
    jsonObj.user_id = selectedUsers[indexUsers]['rowId'];
    jsonObj.AF = af_Array;
    jsonObj.Trend = Trend_Array;
    JSON_OBJECT.push(jsonObj);
}
};

问题陈述 ：更改user_id:123的formula_type的值

尝试以下代码

var currentUserID = '123';
var formulaType = 'FORMULA-1'

Object.keys(JSON_OBJECT).forEach(function(k) {
if (currentUserID == JSON_OBJECT[k]['user_id']) {
    JSON_OBJECT[k]['AF'][0]['formula_type'] = formulaType;
}
});

面临的问题 ：上面的代码更改了user_id:123和user_id:859的formula_type值

结果JSON ：

[
{
    "user_id": "123",
    "AF": [
        {
            "formula_type": 'FORMULA-1',
            "lag": 0
        }
    ],
    "Trend": [
        {
            "is_active": 0
        }
    ]
},
{
    "user_id": "859",
    "AF": [
        {
            "formula_type": 'FORMULA-1',
            "lag": 0
        }
    ],
    "Trend": [
        {
            "is_active": 0
        }
    ]
}
]

帮助将不胜感激。

 var JSON_OBJECT = [ { "user_id": "123", "AF": [ { "formula_type": 0, "lag": 0 } ], "Trend": [ { "is_active": 0 } ] }, { "user_id": "859", "AF": [ { "formula_type": 0, "lag": 0 } ], "Trend": [ { "is_active": 0 } ] } ]; var currentUserID = '123'; var formulaType = 'FORMULA-1' Object.keys(JSON_OBJECT).forEach(function(k) { if (currentUserID == JSON_OBJECT[k]['user_id']) { JSON_OBJECT[k]['AF'][0]['formula_type'] = formulaType; } }); console.log(JSON_OBJECT); 

Answer 1

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <script> $(document).ready(function(){ var currentUserID = '123'; var formulaType = 'FORMULA-1'; var JSON_OBJECT = '[{ "user_id": "123", "AF": [ { "formula_type": 0, "lag": 0 } ], "Trend": [ { "is_active": 0 } ]},{ "user_id": "859", "AF": [ { "formula_type": 0, "lag": 0 } ], "Trend": [ { "is_active": 0 } ]}]'; var obj = jQuery.parseJSON(JSON_OBJECT); // var obj1 = jQuery.parseJSON(JSON_OBJECT); $.each(obj, function(k,value) { if(value.user_id == currentUserID){ JSON_OBJECT.AF = formulaType; obj[k]['AF'][0]['formula_type'] = formulaType; } }) var myJSON = JSON.stringify(obj); console.log(myJSON) }); </script> 

Answer 2

以下代码段有效：

 var JSON_OBJECT = [ { "user_id": "123", "AF": [ { "formula_type": 0, "lag": 0 } ], "Trend": [ { "is_active": 0 } ] }, { "user_id": "859", "AF": [ { "formula_type": 0, "lag": 0 } ], "Trend": [ { "is_active": 0 } ] } ]; var currentUserID = '123'; var formulaType = 'FORMULA-1' Object.keys(JSON_OBJECT).forEach(function(k) { if (currentUserID == JSON_OBJECT[k]['user_id']) { JSON_OBJECT[k]['AF'][0]['formula_type'] = formulaType; } }); console.log(JSON_OBJECT); 

祝好运 ！

Answer 3

请尝试以下操作：

if (JSON_OBJECT.length > 0) {
    JSON_OBJECT.forEach(function(obj, index) {
    if (obj.user_id == 123) {
        if (obj.hasOwnProperty('AF')) {
        obj.AF.forEach(function(obj, index) {
            if (obj.hasOwnProperty('formula_type')) {
            obj.formula_type = 'FORMULA-1';
          }
        });
        }
    }

  });
}

说明：这里JSON_OBJECT是对象的数组。 因此，我们需要先循环到数组中。

的jsfiddle

Answer 4

使用数组map（）方法：

 var jsonObj = [ { "user_id": "123", "AF": [ { "formula_type": 0, "lag": 0 } ], "Trend": [ { "is_active": 0 } ] }, { "user_id": "859", "AF": [ { "formula_type": 0, "lag": 0 } ], "Trend": [ { "is_active": 0 } ] } ]; var currentUserID = '123'; var formulaType = 'FORMULA-1'; jsonObj.map(obj => { if (obj.user_id == currentUserID) { for (var i in obj["AF"]) { obj["AF"][i].formula_type = formulaType; } } }); console.log(jsonObj); 

在循环中使用JavaScript ...

 var jsonObj = [ { "user_id": "123", "AF": [ { "formula_type": 0, "lag": 0 } ], "Trend": [ { "is_active": 0 } ] }, { "user_id": "859", "AF": [ { "formula_type": 0, "lag": 0 } ], "Trend": [ { "is_active": 0 } ] } ]; var currentUserID = '123'; var formulaType = 'FORMULA-1'; for (var i in jsonObj) { if (jsonObj[i]["user_id"] == currentUserID) { for (var j in jsonObj[i]["AF"]) { jsonObj[i]["AF"][j].formula_type = formulaType; } } } console.log(jsonObj); 

Answer 5

问题在于创建JSON， jsonCreator() 。 行jsonObj.AF = af_Array; 没有复制，只是分配了参考。

找到解决方案，并建议使用@ccarton ，将JSON_OBJECT转换为字符串并进行解析。

var currentUserID = '123';
var formulaType = 'FORMULA-1'

var JSON_OBJECT1 = JSON.stringify(JSON_OBJECT); 
JSON_OBJECT = JSON.parse(JSON_OBJECT1)

Object.keys(JSON_OBJECT).forEach(function(k) {
if (currentUserID == JSON_OBJECT[k]['user_id']) {
    JSON_OBJECT[k]['AF'][0]['formula_type'] = formulaType;
}
});