如何在python中动态创建新进程？

Question

这是我的主要功能。 如果我收到新的报价，我需要检查付款。 我有HandleNewOffer（）函数。 但是，如果同时有2个（或更多）要约，则会发生此代码的问题。 买方之一将不得不等到交易结束。 那么这是否有可能使用HandleNewOffer（）函数生成新流程并在同时完成多个事务时将其杀死呢？ 先感谢您。

def handler():
    try:
        conn = k.call('GET', '/api/').json() #connect
        response = conn.call('GET', '/api/notifications/').json() 
        notifications = response['data']
        for notification in notifications:
            if notification['contact']:
                HandleNewOffer(notification) # need to dynamically start new process if notification

    except Exception as err:
        error= ('Error')
        Send(error)

Answer 1

我建议在这里使用“工人池”模式来限制对HandleNewOffer的并发调用量。

concurrent.futures模块提供上述模式的现成实现。

from concurrent.futures import ProcessPoolExecutor

def handler():
    with ProcessPoolExecutor() as pool:
        try:
            conn = k.call('GET', '/api/').json() #connect
            response = conn.call('GET', '/api/notifications/').json() 

            # collect notifications to process into a list
            notifications = [n for n in response['data'] if n['contact']]

            # send the list of notifications to the concurrent workers
            results = pool.map(HandleNewOffer, notifications)

            # iterate over the list of results from every HandleNewOffer call
            for result in results:
                print(result)
        except Exception as err:
            error= ('Error')
            Send(error)

该逻辑将并行处理与计算机拥有的许多CPU内核一样多的报价。