在进行数学运算后如何从1个表中获取数据并插入到另一个表中

Question

我有2表，即AccPurchase和PurchaseProjection 。 AccPurchase中已经有数据，我想从AccPurchase中获取数据，然后添加一些百分比，然后将其插入PurchaseProjection表中。 我有html表单，我正在从表单发送日期和百分比值。 我在所选日期的每一行中都添加了一些百分比，然后插入PurchaseProjection中。

<?php
$date = $_GET['1'];
$percentage = $_GET['2'];
$con = mysqli_connect("localhost","username","pw","db");

$sql = "Select Date, Amount, Paid, Outstanding from 
AccPurchase Where Date='$date'";
$row = mysqli_query($con,$sql);
mysqli_fetch_array($row,MYSQLI_ASSOC);
$date=$row['Date'];
$amount=$row["Amount*('$percentage'/100)"];
$paid=$row['Paid'];
$outstanding=$row['Outstanding'];

$sql1 = "INSERT into PuchaseProjection (`Date`,`Amount`,`Paid`,`Outstanding`) VALUES ('$date','$amount','$paid','$outstanding')";
mysqli_query($con,$sql1);

mysqli_close($con);;

 ?>

Answer 1

我建议您将PDO用于MySQL操作。 对于您的问题，我也有在我的项目中使用的解决方案。 只需在具有相同列名和列数的插入查询之后放置选择查询，它将像超级按钮一样工作。

查询： INSERT into PuchaseProjection (Date,Amount,Paid,Outstanding) Select Date, Amount+(Amount * :percentage / 100) as Amount, Paid, Outstanding from AccPurchase Where Date=:date

：percentage和：date表示pdo语句中的占位符。访问PDO官方手册

Answer 2

 <?php
 $date = $_GET['1'];
 $percentage = $_GET['2'];
 $con = mysqli_connect("localhost","username","pw","db");

 $sql = "Select Date, Amount, Paid, Outstanding from 
 AccPurchase Where Date='$date'";
 $row = mysqli_query($con,$sql);
 mysqli_fetch_array($row,MYSQLI_ASSOC);
 $date=$row['Date']/*do the operation,if any*/;
 $amount=$row["Amount"]*($percentage/100);
  $paid=$row['Paid']/*do the operation,if any*/;
  $outstanding=$row['Outstanding']/*do the operation,if any*/;

  $sql1 = "INSERT into PuchaseProjection 
  (`Date`,`Amount`,`Paid`,`Outstanding`) VALUES 
  ('$date','$amount','$paid','$outstanding')";
  mysqli_query($con,$sql1);
   mysqli_close($con);

  ?>

尝试这个