命令行参数第二大数字 - C 程序

Question

#include<stdio.h>
#include<conio.h>

void main()
{
int a[50];
int n,i,large,s_large;
clrscr();

printf("\n Enter number of elements: ");
scanf("%d",&n);

printf("\n Enter the elements: ");
for(i=0;i<n;i++)
{
    scanf("%d",&a[i]);
}

large=s_large=a[0];

for(i=1;i<n;i++)
{
    if(large<a[i])
    {
        s_large=large;
        large=a[i];
    }
    else if(s_large<a[i] && a[i]!=large)
    {
        s_large=a[i];
    }
}

printf("\n The Second Largest Element in the given Array: %d", s_large);
getch();
}

以上是找出c中第二大数字的工作代码。 我是命令行参数的新手。 所以请帮助我将这篇文章转换为命令行参数。

Answer 1

您需要将argc和argv用于c命令行参数。 命令行参数可在argv数组中找到 - argv[1], argv[2] etc 。 参数的数量可以在argc中找到。

您按如下方式执行程序。

./exe 1 2 4 6 3 5
 In this case `argc` will have `7` and argv will have as following
 arg[0]= exe,arg[1] = 1,arg[2] = 2,arg[3] = 4,arg[4] = 6,arg[5] = 3 and arg[6] = 5.

您的代码如下所示。

#include <stdio.h>
#include <conio.h>
#include <limits.h>

int main(int argc, char *argv[])
{
   int i=0,num=0,large=INT_MIN, s_large=INT_MIN;

  printf("Number of arguments: %d\n", argc);
   //argv[0] is the program name
  for(i=1; i<argc; i++)
  {
     if(sscanf(argv[i], "%d", &num) !=1)
      break; //Not an integer

     printf("%d\n", num);
     if(large<num)
     {
        s_large=large;
        large=num;
     }
     else if(s_large<num && num !=large)
     {
       s_large=num;
     }

   }

   printf("\n\nThe Largest Number is %d",s_large);

   getch();
   return 0; 
}