如何重复3次功能

Question

我正在创建此函数来测试用户输入（作为猜测）是否正确。

def check_guess():
   letter = "d"
   guess = input("What is your guess: ")
   if guess.isalpha() == False:
       print("This is invalid")
   elif guess.lower() > letter:
       print("This too high")
   elif guess.lower() < letter:
       print("this is too low")
   else:
       print("that is correct")

check_guess()

所以我创建了这段代码，并且没有问题。 但是，我现在的任务是必须给用户3次尝试。 如果用户获得正确答案，则将打印“正确”，游戏结束。 但是，如果他们在所有3次尝试中均失败，则类似于“游戏结束”。

如何创建/复制代码以使其能够执行此操作？

Answer 1

使用for循环及其else子句。 循环的else子句仅在没有中断循环的情况下运行。

首先让函数返回一个值，以指示用户是否正确猜测。 否则，将很难与之交互：

def check_guess():
    letter = "d"
    guess = input("What is your guess: ")
    if not guess.isalpha():
        print("This is invalid")
        return False
    guess = guess.lower()
    if guess == letter:
        print("that is correct")
        return True
    if guess > letter:
        print("This too high")
    else:
        print("this is too low")
    return False

现在，您可以准确地调用该函数三次，或者直到用户猜对为止（以先到者为准）：

for _ in range(3):
    if check_guess():
        break
else:
    print('you failed')

当check_guess返回True表示成功时，我们会break循环，确保不会触发else子句。 如果三个迭代完成并且用户从未做出正确的猜测，则触发该子句。

Answer 2

def check_guess():
   letter = "d"
   guess = input("What is your guess: ")
   if guess.isalpha() == False:
       print("This is invalid")
       return False
   elif guess.lower() > letter:
       print("This too high")
       return False
   elif guess.lower() < letter:
       print("this is too low")
       return False
   else:
       print("that is correct")
       return True

for i in range(0,3):
     status = check_guess()
     If status:
         print(“success”)
         break
else:
     print(“fail”)

Answer 3

如果用户正确，则需要返回，然后如果不增加计数器，则需要返回。 这样的事情应该起作用：

count = 0
while count < 3:
    if check_guess():
        # he's right
        break
    else:
        # he's wrong
        count += 1
if count >= 3:
    print("You lose !")
else:
    print("You win !")

Answer 4

您可以通过以下方式进行操作：

def check_guess():
    status = False
    letter = "d"
    guess = input("What is your guess: ")
    if guess.isalpha() == False:
        print("This is invalid")
    elif guess.lower() > letter:
        print("This too high")
    elif guess.lower() < letter:
        print("this is too low")
    else:
        print("that is correct")
        status = True
    return status

for i in range(3):
    status = check_guess()
    if status:
        break
else:
    print "Gameover"

Answer 5

 c=0
 def check_guess():
 letter = "d"
 guess = input("What is your guess: ")
 if guess.isalpha() == False:
   print("This is invalid")
   c++
 elif guess.lower() > letter:
   print("This too high")
   c++
 elif guess.lower() < letter:
   print("this is too low")
   c++
 else:
   print("that is correct")
   c=4
 if c<=3
   check_guess()