Python Pandas从列表中将多个SAS文件读取到单独的数据框中

Question

我正在读取许多SAS文件，如下所示：

demography = pd.read_sas("demography.sas7bdat", encoding = 'latin-1') adverse_event_ds = pd.read_sas("adverse_event_ds.sas7bdat", encoding = 'latin-1') rpt10344 = pd.read_sas("rpt10344.sas7bdat", encoding = 'latin-1') vaccine_administration = pd.read_sas("vaccine_administration.sas7bdat", encoding = 'latin-1') lab_tests_blood_chemistry_ds = pd.read_sas("lab_tests_blood_chemistry_ds.sas7bdat", encoding = 'latin-1') lab_tests_hematology_ds = pd.read_sas("lab_tests_hematology_ds.sas7bdat", encoding = 'latin-1') lab_tests_miscellaneous_ds = pd.read_sas("lab_tests_miscellaneous_ds.sas7bdat", encoding = 'latin-1') vital_signs = pd.read_sas("vital_signs.sas7bdat", encoding = 'latin-1')

我希望能够将其替换为以下内容：

datasets = ["demography", "adverse_event_ds", "rpt10344", "vaccine_administration", "lab_tests_blood_chemistry_ds", "lab_tests_hematology_ds", "lab_tests_miscellaneous_ds", "vital_signs"]

for dataset in datasets: dataset = pd.read_sas(dataset+".sas7bdat", encoding = 'latin-1')

但是当我做类似的事情时： demography.info()

我得到： NameError: name 'demography' is not defined

到底发生了什么，我该如何解决？

Answer 1

这是在每次迭代时分配给dataset ，而不是创建新变量（例如， demography ， rpt10344等）。

我将使用数据集字典，如下所示：

dsd = {}
for dataset in datasets:
    dsd[dataset] = pd.read_sas(dataset+".sas7bdat", encoding = 'latin-1')

或更Python的路线：

dsd = { d : pd.read_sas(d + ".sas7bdat", encoding = 'latin-1') for d in datasets }

我强烈建议您不要出于此处和此处说明的原因而为各个变量名分配变量，但是如果您绝对必须可以使用

for d in datasets:
    globals()[d] = pd.read_sas(d + ".sas7bdat", encoding = 'latin-1')