错误：预期对标准“ Match URL：xyz”的一个匹配请求，未找到

Question

我现在不知所措。 我正在尝试测试拦截器：

测试：

const testBedBase = {
  imports: [HttpClientTestingModule],
  providers: [
    ApiService,
    CacheService,
    { provide: HTTP_INTERCEPTORS, useClass: CacheInterceptor, multi: true }
  ]
};

describe('CacheInterceptor with cached data', () => {
  let httpMock: HttpTestingController;
  let apiService: ApiService;
  let cacheService: CacheService;

  beforeEach(() => {
    TestBed.configureTestingModule(testBedBase);
    httpMock = TestBed.get(HttpTestingController);
    apiService = TestBed.get(ApiService);
    cacheService = TestBed.get(CacheService);
  });

  afterEach(() => {
    httpMock.verify();
  });

  it('should respond with cached data if available', async( () => {
    const testUrl = `http://localhost:3000/api/v1/employee/123`;
    spyOn(cacheService, 'get').and.returnValue(mockResponse);
    apiService.getEmployee('123').subscribe(res => {

      // apiService calls http://localhost:3000/api/v1/employee/123 as tested in the interceptor

      expect(res).toBeTruthy();
      expect(res).toBe(mockResponse);
    });
    const req = httpMock.expectOne(testUrl);
    req.flush(mockResponse);
  }));
})

intercept(req: HttpRequest<any>, next: HttpHandler) {
    const cachedResponse = this.cache.get(req.url);
    console.log(cachedResponse, req.url); // this returns the http://localhost:3000/api/v1/employee/123 as seen in the getEmployee request
    return cachedResponse ? Observable.of(cachedResponse) : this.sendRequest(req, next);
  }

据我了解， spyOn(cacheService, 'get').and.returnValue(mockResponse); 应该在拦截器中设置this.cache.get请求的响应，但事实并非如此。 而且，我不断得到： Failed: Expected one matching request for criteria "Match URL: http://localhost:3000/api/v1/employee/123", found none.

如果删除间谍，则错误会消失，但在这种情况下，我不会取消服务的响应。

茉莉3.1.0角7

Answer 1

所以我在这里发生了两件事。 由于我试图返回数据而不发送实际的HTTP请求，因此我不应该告诉httpMock期望该请求。 我应该告诉它httpMock.expectNone(testUrl) 。 其次，我与间谍发送的模拟响应不是订阅所期望的实际HttpResponse，而是发送一个对象。 所以我需要做一个：

new HttpResponse({ body: employee.data.employee, status: 200 });

送回间谍。

希望这可以节省别人的工作时间:)