我在AsyncTask的doInBackground（）中收到错误

Question

我在位于asyncTask的doInBackground（）部分的AsyncHttpClient部分中得到错误。 如何摆脱错误？ 错误接收行如下所示。

错误：执行doInBackground（）时发生错误

public class BackgroundTask2 extends AsyncTask<String,Void,String> {

        protected Void doInBackground(String... params) {

            Bundle veri = getIntent().getExtras();
            sorguYil = veri.getString("yil");
            sorguAy = veri.getString("tarih");

            sorguAy2 = sorguAy.replace(" ", "");
            sorgu = "ehliyet" + sorguYil + sorguAy2;
            s = kelimeGetir(sorgu); // I am getting the error here
            return s;}

protected void onPostExecute(String aVoid) {
            super.onPostExecute(aVoid);

        if (aVoid.equals("internet")){
            Toast.makeText(sorularActivity.this, "Lütfen internet bağlantınızı kontrol edin!", Toast.LENGTH_SHORT).show();
            progressDialog.dismiss();
            Intent intent = new Intent(getApplicationContext(),SinavSecimiActivity.class);
            startActivity(intent);
            overridePendingTransition(R.anim.slide_in_left,R.anim.slide_out_right);

        }else if (aVoid.equals("onay")){
            progressDialog.dismiss();
        }

    }

kelimeGetir（sorgu）

private String kelimeGetir(String sorgu) {

        AsyncHttpClient client = new AsyncHttpClient();
        RequestParams params = new RequestParams();
        params.put("sorgu", sorgu);
        client.post("https://www....php", params, new TextHttpResponseHandler()
//****ERROR {

            public void onFailure(int statusCode, Header[] headers, String responseString, Throwable throwable) {
                fnDu = "internetEr";

            }

            public void onSuccess(int statusCode, Header[] headers, String responseString) {

                try {

                    txtSoruSayisi.setText(soruSayisi + " / 50");

                    JSONObject object = new JSONObject(responseString);
                    JSONArray array = object.getJSONArray("soruVeri");
                    JSONObject sorular = array.getJSONObject(sayac);

                } catch (JSONException e) {
                    e.printStackTrace();
                }
            }
          fnDu = "onay";
        });

     return fnDu;

    }

错误在此处输入图片描述

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Answer 1

正如@Uday Nayak所说，您无法在doInBackground方法上访问UI元素，这将导致崩溃（它以不同的线程运行）。 但是如果您必须这样做，请将其包裹

runOnUiThread(() -> {
            // to UI access
        });

或创建处理程序以访问主线程以显示您的吐司