有没有办法更新lambda函数内的RDD

Question

我需要找到一些单词的数量，以便它可以与某些单词的前一批次有所不同。

示例i必须从流数据中找到字数。 找到计数的单词是(test,jack)如果我的第一批有单词(test 5),(kite 2),(jack 3),(pen 5)第二批有数据(test 2),(jack 1),(kite 1),(pen 1)第二批的输出应如下:( (test 3),(jack 2) //test(5-3) and jack(2-1)

..........

JavaPairRDD<String, Integer> initialRDD=jsc.sparkContext().parallelizePairs(tuples1);
 JavaPairDStream<String,Integer> joinedDstream= pairstream.transformToPair(new Function<JavaPairRDD<String, Integer>, JavaPairRDD<String, Integer>>() {
           @Override
           public JavaPairRDD<String, Integer> call(JavaPairRDD<String, Integer> v1) throws Exception {

               JavaPairRDD<String, Integer> modRDD  = v1.join(initialRDD).mapToPair(new PairFunction<Tuple2<String, Tuple2<Integer, Integer>>, String, Integer>() {
                   @Override
                   public Tuple2<String, Integer> call(Tuple2<String, Tuple2<Integer, Integer>> stringTuple2Tuple2) throws Exception {
                       return new Tuple2<>(stringTuple2Tuple2._1(), (stringTuple2Tuple2._2()._2 - stringTuple2Tuple2._2()._2));
                   }
               });
               return modRDD;      
initialRDD=modRDD.  //how to do this as lambda expressions only allow final variable.              
expressions require final variable.
           }
       });