Flutter Unexpected end of input (at character 1)

Question

如何修复此错误

[错误：flutter/lib/ui/ui_dart_state.cc(148)] 未处理的异常：FormatException：意外的输入结束（在字符 1）E/flutter（11841）：E/flutter（11841）：^ E/flutter（11841） ): E/颤振 (11841):

0 _ChunkedJsonParser.fail (dart:convert/runtime/libconvert_patch.dart:1357:5) E/flutter (11841):

1 _ChunkedJsonParser.close (dart:convert/runtime/libconvert_patch.dart:510:7) E/flutter (11841):

2 _parseJson (dart:convert/runtime/libconvert_patch.dart:30:10) E/flutter (11841): #3 JsonDecoder.convert

(dart:convert/json.dart:491:36) E/flutter (11841): #4
JsonCodec.decode (dart:convert/json.dart:149:41) E/flutter (11841): #5 storeSync (package:reborn_next_job02/Cache/syncApi.dart:19:29) E/flutter (11841): E/颤振（11841）：#6
_ListPageState.initState。 (package:reborn_next_job02/ui/AssetRegisters.dart:54:9) E/flutter (11841): #7 _rootRunUnary (dart:async/zone.dart:1132:38) E/flutter (11841): #8 _CustomZone.runUnary (dart:async/zone.dart:1029:19) E/flutter (11841): #9
_CustomZone.runUnaryGuarded (dart:async/zone.dart:931:7) E/flutter (11841)：#10 _CustomZone.bindUnaryCallbackGuarded。 (dart:async/zone.dart:968:26) E/flutter (11841): #11
_rootRunUnary (dart:async/zone.dart:1136:13) E/flutter (11841): #12 _CustomZone.runUnary (dart:async/zone.dart:1029:19) E/flutter (11841): #13 _CustomZone。绑定一元回调。 (dart:async/zone.dart:952:26) E/flutter (11841): #14
_Timer._runTimers (dart:isolate/runtime/libtimer_impl.dart:382:19) E/flutter (11841): #15 _Timer._handleMessage (dart:isolate/runtime/libtimer_impl.dart:416:5) E/flutter (11841) ): #16 _RawReceivePortImpl._handleMessage (dart:isolate/runtime/libisolate_patch.dart:171:12)

同步API.dart

storeSync(String url, String token) async {
  final response = await http.get(
    '$url/v1.0/SyncDataTable',
    headers: {'Authorization': 'Bearer $token'},
  );


  final jsonResponse = json.decode(response.body);
  SyncModel model = SyncModel.fromJson(jsonResponse);
  int length = model.data.length;

HelperSync().display()).elementAt(i)?.syn_ChangeSequence,


  for (int i = 0; i < length; i++) {
    if ((await HelperSync().display()).elementAt(i)?.syn_TableName == model.data[i].syn_TableName) {
      if ((await HelperSync().display()).elementAt(i)?.syn_ChangeSequence != model.data[i].syn_ChangeSequence) {
        switch (i) {
          case 21:
            {
              await HelperDatabase1().storeRegister(url, token);
            }
            break;
        }
      }
    }
  }
}

Answer 1

“FormatException”错误通常是由编码问题引起的。 要解决此问题，您可以将response.body为 HashMap 以在解码之前查找结果 Map<String, dynamic>。

// final jsonResponse = json.decode(response.body); // we can skip
SyncModel model = SyncModel.fromJson(response.body as Map<String, dynamic>>);