如何在Python中使用re.sub？ [重复]

Question

这个问题已经在这里有了答案：

• 替换2个字符串之间的所有文本python 5 answers

Text = "<a> text </a> <c> code </c>"                                               

我想在python中删除<c> code </c>语句

output = "<a> text </a>"

Answer 1

您可以使用re.sub ：

>>> import re
>>> text = "<a> text </a> <c> code </c>"
>>> new_text = re.sub(r'<c>.*?</c>', '', text)
>>> new_text
<a> text </a> 

Answer 2

在这里，我们可以简单地添加开始和结束标记，以及捕获组之间的所有标记：

# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility

import re

regex = r"(<a>.+<\/a>)"

test_str = "<a> text </a> <c> code </c>"

matches = re.finditer(regex, test_str, re.MULTILINE)

for matchNum, match in enumerate(matches, start=1):

    print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))

    for groupNum in range(0, len(match.groups())):
        groupNum = groupNum + 1

        print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))

# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.

演示版

 const regex = /(<a>.+<\\/a>).+/gm; const str = `<a> text </a> <c> code </c>`; const subst = `$1`; // The substituted value will be contained in the result variable const result = str.replace(regex, subst); console.log('Substitution result: ', result); 

Answer 3

 import re
 text = "<a> text </a> <c> code </c>"
 rg = r"<c>.*<\/c>"
 for match in re.findall(rg, text):
     text = text.replace(match, "")