有没有办法打开来自webview上的信号的链接？

Question

我在我的flutter应用程序中使用webview小部件我想在用户点击通知时打开一个链接，该链接来自我试图制作的一个信号的附加数据，但它不起作用
我的代码：

import 'package:flutter/material.dart';
import 'dart:async';
import 'package:flutter_webview_plugin/flutter_webview_plugin.dart';
import 'package:onesignal/onesignal.dart';

void main() => runApp(new MyApp());

class MyApp extends StatefulWidget {
@override
_MyAppState createState() => new _MyAppState();
}

class _MyAppState extends State<MyApp> {
String _debugLabelString = "";
String url = "https://www.google.com";


@override
void initState() {
super.initState();
initPlatformState();
}

Future<void> initPlatformState() async {
if (!mounted) return;

OneSignal.shared.setLogLevel(OSLogLevel.verbose, OSLogLevel.none);

OneSignal.shared.setRequiresUserPrivacyConsent(_requireConsent);

var settings = {
  OSiOSSettings.autoPrompt: false,
  OSiOSSettings.promptBeforeOpeningPushUrl: true
};

OneSignal.shared.setNotificationReceivedHandler((notification) {
  this.setState(() {
    url = notification.payload.additionalData['url'].toString() ;

  });
});

OneSignal.shared
    .setNotificationOpenedHandler((OSNotificationOpenedResult result) {
  this.setState(() {
  // the value of result.notification.payload.additionalData['url'] = 
  // https://www.facebook.com/
    url = result.notification.payload.additionalData['url'].toString() ;
  });
});


// NOTE: Replace with your own app ID from https://www.onesignal.com
await OneSignal.shared
    .init("086d22bd-5539-4849-9db2-01589fd3429d", iOSSettings: settings);

OneSignal.shared
    .setInFocusDisplayType(OSNotificationDisplayType.notification);


}



@override
Widget build(BuildContext context) {
return new MaterialApp(
home: new Scaffold(
appBar: new AppBar(
title: const Text('OneSignal Flutter Demo'),
backgroundColor: Color.fromARGB(255, 212, 86, 83),
),
body:  WebviewScaffold(
        url: url,

        withJavascript: true,
      )
  ),
);
}
}

我把facebook.com放在其他数据中，它显示谷歌页面不是facebook如何让它显示我放在额外数据上的保存值

Answer 1

setNotificationReceivedHandler 在前台设备上收到通知时创建回调。

对于“on notification open”回调（如果它在后台，则setNotificationOpened ），使用setNotificationOpened处理程序。

Flutter事件处理程序引用 。

如果您希望在后台处理此问题而不管通知是否已打开，请参阅背景通知 （注意：请准备编写本机代码，此处）