将多个列表组合成单个数组

Question

{ "data": [ {"firstName": "Achmad"}, {"lastName": "a"} ] }和这个我的脚本var body = request.body;for(var i = 0;i < body.data.length;i++){var obj = body.data[i];var keyes = Object.keys(obj);} var keyes = Object.keys(obj); 是这样的列表[ 'firstName' ] [ 'lastName' ]我想要这样['firstName', 'lastName']

之前谢谢。

Answer 1

编辑：您可以concat数组的每个项目：

const body = {
  "data": [
    {"firstName": "Achmad"},
    {"lastName": "a"}
  ]
};

let result = [];
for (item of body.data) {
  result = result.concat(Object.keys(item));
}

console.log(result); // -> ['firstName', 'lastName']

Answer 2

假设每个数组都是父数组的元素，实现这一点的一种方法是使用Array.prototype.reduce ：

 const flat = [ ["aku"], ["dia"], ["ia"] ].reduce((accum, el) => accum.concat(el), []) console.log(flat);

Answer 3

也许你想做这样的事情

var body = request.body;
var keyes = [];
for(var i = 0; i < body.data.length; i++){
    var obj = body.data[i];
    keyes.push( Object.keys(obj) );
}