将字符串“YYYYMMDDHHMMSS”转换为Python中的时间戳[重复]

Question

这个问题在这里已经有了答案：

仅使用字符串 format() 方法的 Python 格式日期1 个回答

2年前关闭。

我需要帮助在 python 中将此字符串 '20190625091115' 转换为时间戳 '25-06-2019 09:11:15'。 格式为'YYYYMMDDHHMMSS > 格式为'DD-MM-YYYY HH:MM:SS'。

Answer 1

第一部分是创建日期时间对象：

from datetime import datetime

date_string = "20190625091115"
format_date = datetime.strptime(date_string, '%Y%m%d%H%M%S'))
After which format date is:

print(format_date)
2019-06-25 09:11:15

Little clarification here, on python reference page, you can see definition for '%Y%m%d%H%M%S') format specifiers I used.

%Y: Year with century as a decimal number, e.g. 1970, 1988, 2001, 2013
%m: Month as a zero-padded decimal number (e.g. 01, 02, ..., 12)
%d: Day of the month as a zero-padded decimal number (e.g. 01, 02, ..., 31)
%H: Hour (24-hour clock) as a zero-padded decimal number (e.g 00, 01, ..., 23)
%M: Minute as a zero-padded decimal number (e.g 00, 01, ..., 59)
%S: Second as a zero-padded decimal number (e.g. 00, 01, ..., 59)
%f: Microsecond as a decimal number, zero-padded on the left (000000, 000001, ..., 999999)
%z: UTC offset in the form +HHMM or -HHMM, empty string if the the object is naive, (empty or +0000, -0400, +1030)