获取此矩阵的对角线

Question

我正在尝试创建一个 function ，它将从我的单词搜索难题的列表（即矩阵）中的列表中获取对角线。

def get_left_up (start_x, start_y, board):
word = []
for row in range (start_x, -1,-1):
    for col in range (start_y,-1, -1):
        word.append(board[row][col])
word = ''.join(word)
return word

get_left_down (start_x, start_y, board):
word = []
for row in range (start_x,len(board)):
    for col in range (start_y,-1,-1):
        word.append(board[row][col])
word = ''.join(word)
return word

def get_right_up (start_x, start_y, board):
word= []
for row in range (start_x,-1,-1):
    for col in range (start_y,len(board)):
        word.append(board[row][col])
word = ''.join(word)
return word

def get_right_down (start_x, start_y, board):
word = []
for row in range (start_x, len(board)):
    for col in range (start_y,len(board)):
      word.append(board[row][col])
word = ''.join(word)
return word

截至目前，那些我应该处理的功能。 然而，有些不对劲。 我打算将与正在搜索的单词匹配的第一个字母的坐标的 arguments 放入板上，并从对角线的每个方向连接字符。

Answer 1

对于右下对角线，您需要在同一迭代中增加 x- 和 y- ，而不是循环遍历特定行的所有列条目。

def get_right_down (start_x, start_y, board):
   word = []
   col = start_y
   for row in range (start_x, len(board)):
      if col >= len(board):
         break
      word.append(board[row][col])
      col = col + 1
   return ''.join(word)