在 codeigniter 中编写此 mysql 查询

Question

我需要帮助在 CodeIgniter 中编写这个 MySQL 查询

SELECT *, ABS( post_code - 2015 ) AS distance FROM list_data WHERE business_name LIKE '%cash%' ESCAPE '!' ORDER BY distance LIMIT 6

2015 年和'%cash%'来自输入字段

到目前为止，我已经这样写了，但是没有用

public function searchListing($data, $location) {
        $this->db->select('(SELECT *, ABS(`post_code`-' $location' AS distance FROM `list_data` ORDER BY distance)', FALSE);
        $this->db->like('business_names', $data);
        $query = $this->db->get();
        return $query->result();
    }

下图是表格的样子

下图是我想在 codeigniter 中写的查询

谁能帮我？ 谢谢

Answer 1

这是问题的解决方案

public function searchListing($data, $location) {
    $q = $this->db->select('*, ABS( post_code - '.$location.') AS distance')
         ->from('list_data')
         ->like('business_name', $data)
         ->order_by('distance')
         ->limit(6)
         ->get()
         ->result();
    return $q;

感谢来自 CodeIgniter 论坛的@Chivinsdev 的解决方案