使用美丽的汤从标签中提取“href”

Question

我在 html 中有以下标签，我只想提取 href 内容，即 Quatermass_2_Vintage_Movie_Poster-61-10782 和 Hard Day's Night

<span class="small">
                                Ref.No:10782<br/>
<a href="Quatermass_2_Vintage_Movie_Poster-61-10782" title="Click for more details and a larger picture of Quatermass 2">
                                Click for more details and a larger picture of <b>Quatermass 2</b>
</a>
</span>, <span class="small">
                                Ref.No:10781<br/>
<a href="Hard_Day__039_s_Night_Vintage_Movie_Poster-61-10781" title="Click for more details and a larger picture of Hard Day's Night">
                                Click for more details and a larger picture of <b>Hard Day's Night</b>
</a>
</span>

以下 python 代码使我只能找到整个标签

html = ['table2.html']

with open("table2.html", "r") as f:
    contents = f.read()


soup = BeautifulSoup(contents, "lxml")

for name in soup.find_all("span", {"class": "small"}):
    print(name)

但是无法仅 select href。 我努力了

for name in soup.find_all("span", {"class": "small"}.get(href)):
    print(name) 

我也尝试将 href 引用放在打印语句中

for name in soup.find_all("span", {"class": "small"}:
    print(name.get('href'))         

有人可以帮忙吗？

Answer 1

获得span标签后，您需要找到a标签，然后获取href属性。

像这样的东西会起作用：

for name in soup.find_all("span", {"class": "small"}):
    print(name.find("a").get("href"))

Answer 2

您可以使用正则表达式来提取值，如下所示：

import re

input = "adde <a href=\"coedd.com\" > algo</a>";

patt= "href=\"[a-zA-Z0-9_\-\.]+\""

search = re.findall(patt, input, re.I)

print search

这将返回一个包含所有巧合的数组。

我希望有用。

问候。