将对象分配给数组C ++

Question

我对C ++还是很陌生，并且在上周一直在努力完成一部分作业。

我知道这很简单，但是我无法正确地解决问题。

我需要为我创建的类（Employee）创建四个对象，并将它们分配给我创建的数组

这是我的默认构造函数：

Employee() // Deafault Constructor 
    {
        empNumber = 00000;
        hours, payRate = 0;
        name = "Name";
    }

我试图用不同的数据创建4个对象保存到数组元素中：

int Employees[4];
    Employees[0] = Employee(67258, 40, 35, "Craig");
    Employees[1] = Employee(25387, 30, 20, "Carol");
    Employees[2] = Employee(11945, 38, 30, "Suzie");
    Employees[3] = Employee(90832, 28, 40, "Sam");

就像我说的，基本上是全新的，我一直在搜寻暴风雨，但没有成功。

欢迎任何帮助或建议，甚至链接！

这是我的整个代码：

class Employee
{
private:

    int empNumber;
    string name;
    double hours, payRate;

public:

    Employee() // Deafault Constructor 
    {
        empNumber = 00000;
        hours = 0;
        payRate = 0;
        name = "Name";
    }

    Employee(int e_empNumber, double e_hours, double e_payRate, string e_name) // Non-Default Constructor
    {
        empNumber = e_empNumber;
        hours = e_hours;
        payRate = e_payRate;
        name = e_name;
    }

    void getEmployeeData()
    {
        cout << "Employee #: " << empNumber << ' ';
        cout << "Name: " << name << ' ';
        cout << "Hours worked: " << hours << ' ';
        cout << "Pay Rate: " << payRate << endl;
    }

};

int main()
{
    int Employees[4];
    Employees[0] = Employee(67258, 40, 35, "Craig");
    Employees[1] = Employee(25387, 30, 20, "Carol");
    Employees[2] = Employee(11945, 38, 30, "Suzie");
    Employees[3] = Employee(90832, 28, 40, "Sam");

    system("pause");
    return 0;
}

和错误

Answer 1

这样做以创建并填补员工：

Employe employees[4];
    employees[0] = Employee(67258, 40, 35, "Craig");
    employees[1] = Employee(25387, 30, 20, "Carol");
    employees[2] = Employee(11945, 38, 30, "Suzie");
    employees[3] = Employee(90832, 28, 40, "Sam");

您所做的只是创建一个整数数组。 在这里，您将看到如何做：

Type variable_name[size];

Answer 2

感谢大家的帮助！ 我按规范工作了！

这是我的最终代码：

#include <iostream>
using namespace std;




class Employee
{
private:

    int empNumber;
    string name;
    double hours, payRate;

public:

    Employee() // Deafault Constructor 
    {
        empNumber = 00000;
        hours = 0;
        payRate = 0;
        name = "Name";
    }

    Employee(int e_empNumber, double e_hours, double e_payRate, string e_name) // Non-Default Constructor
    {
        empNumber = e_empNumber;
        hours = e_hours;
        payRate = e_payRate;
        name = e_name;

        void getEmployeeData();
        {
            cout << "Employee #: " << empNumber << " - ";
            cout << "Name: " << name << " - ";
            cout << "Hours worked: " << hours << " - ";
            cout << "Pay Rate: " << payRate << endl;
        }
    }



};

int main()
{
    Employee Employees[4];
    Employees[0] = Employee(67258, 40, 35, "Craig");
    Employees[1] = Employee(25387, 30, 20, "Carol");
    Employees[2] = Employee(11945, 38, 30, "Suzie");
    Employees[3] = Employee(90832, 28, 40, "Sam");

    for (int i = 0; i < 3; i++)
    {

        void getEmployeeData();
    }

    system("pause");
    return 0;
}

这将删除存储在数组中的Employee数据

Answer 3

只是想增加一点见解。

当您致电：

Employee Employees[4];

默认的ctor将被调用以初始化数组。 因此，将自动创建四个对象。 然后，当您执行作业时：

Employees[0] = Employee(67258, 40, 35, "Craig");
Employees[1] = Employee(25387, 30, 20, "Carol");
Employees[2] = Employee(11945, 38, 30, "Suzie");
Employees[3] = Employee(90832, 28, 40, "Sam");

使用参数化的ctor创建四个新对象，它将替换最初创建的四个对象。 因此，最初的那些没有用（因为它们从未被使用过），只是为了浪费而制作的。

您可以通过添加以下内容来验证我所说的内容：

要默认的ctor

cout << "default ctor" << endl;

要参数化的ctor

cout << "parameterized ctor" << endl; 

如果要避免对象的多重构造，可以使用以下方法：

Employee Employees[4] = {
  Employee(67258, 40, 35, "Craig"),
  Employee(25387, 30, 20, "Carol"),
  Employee(11945, 38, 30, "Suzie"),
  Employee(90832, 28, 40, "Sam")
};

这不会调用默认的ctor并且只会构造四个Employee对象。

另外，您可以使用std::vector （ #include <vector> ），它使您可以灵活地调整大小，并且如果使用push_back函数，则不使用默认ctor 。