为什么我的try catch出现错误以及如何解决

Question

我正在尝试打印出与电话号码序列相关的每个单词。 我的某些代码使用了try catch，在第二次尝试中却收到了错误，但在第一次尝试中没有。

这是代码。 我在第二次尝试捕获时收到错误。

//create arraylist
    SLList[] numberWordList=new SLList[9999999-2222222+1];
    for(int i=0;i<9999999-2222222+1;i++)
    {
        numberWordList[i]=new SLList();
    }//end for
    // create an arraylist with SLList elements
    int [] letterToNumber=
    {2,2,2, //correspond to ABC
     3,3,3,                //DEF
     4,4,4,
     5,5,5,
     6,6,6,
     7,7,7,7,
     8,8,8,        
     9,9,9,9,};

    try{String word;
        Scanner inputFromWordList=new Scanner(new File("../EnglishWordList.txt"));
        int indexToWords;
        while(inputFromWordList.hasNextLine())
        {
           word=inputFromWordList.nextLine().trim();
           if(word.length()==7)
           {
               indexToWords=0;
               for(int i=0;i<6;i++)
               {
                   indexToWords+=letterToNumber[Character.toLowerCase(word.charAt(i))-'a'];
                   indexToWords*=10;
               }//end for
               indexToWords+=letterToNumber[Character.toLowerCase(word.charAt(6))-'a'];
               numberWordList[indexToWords-2222222].append(word);
           }//end if
        }//end while
        inputFromWordList.close();
    }
     catch (IOException e){System.out.println(e.getMessage());}
//end try
    int count=0;

    try{String number=null;
    Scanner inputFromUser=new Scanner(System.in);
    boolean validNumber;
    System.out.println("Please enter a valid phone number that containts 2-9 only. Put in bye when 
 finished");
    while(inputFromUser.hasNextLine())
    {
        number=inputFromUser.nextLine().trim();
        if(number.toLowerCase()=="bye")
            break;//jump out of while
        if(number.length()!=7)
        {
            System.out.println("Phone number invalid");
            System.out.println("Please input a valid phone number that contains 2-9 only");
            break;
        }//end if
        char tempChar;
        for(int i=0;i<7;i++)
        {
            tempChar=Character.toLowerCase(number.charAt(i));
            if(!((tempChar>='2')&&(tempChar<='9')))
            {
                System.out.println("Phone number invalid");
                validNumber=false;
                break;
            }//end if
            if(validNumber=false)
            {
            System.out.println("Phone number invalid");
            System.out.println("Please input a valid phone number that contains 2-9 only");
            break;
            }//end if
            count++;
        }//end for
    }//endwhile
    numberWordList[Integer.parseInt(number)-2222222].print();

    }//end try2
     catch (IOException e){System.out.println(e.getMessage());}

我没有收到第一个捕获的错误，但是我得到了第二个捕获的错误。 我该如何解决？