Windows 上 Python 3.6 subprocess.run() 中的 7z 命令

Question

我有一个 python 脚本，它应该使用命令运行 7z.exe：“x”并使用 subprocess.run() 切换“-o”。 脚本如下：

import subprocess as sb


zipperpath = "C:\\Program Files\\7-zip\\7z.exe"
dirname ="C:\\Users\\ajain\\Desktop\\TempData"
archivename="UnprocessedData_v3.7z"
outputfilename="foo"

sb.run([zipperpath,"x",os.path.join(dirname,archivename)," -o",os.path.join(dirname,outputfilename)])

输出是： 尽管返回码为 0，但 zip 永远不会被解压缩。

Answer 1

试试这个：

import subprocess

# variable cmd is is your command line , like you put in your console 
cmd='7z.exe x UnprocessedData_v3.7z'

process = subprocess.Popen(cmd,shell=True,stdin=None,stdout=subprocess.PIPE,stderr=subprocess.PIPE)
# The output from your shell command in an array
result=process.stdout.readlines()
if len(result) >= 1:
    for line in result:
        print(line)