创建一个可以在对象数组中搜索元素的函数？

Question

我有这个对象数组：

var person = [
{firstName: "Josh", lastName: "Doe", age: 50, eyeColor: "blue"},
{firstName: "Jake", lastName: "Denver", age: 34, eyeColor: "blue"},
{firstName: "Sam", lastName: "Kiszka", age: 20, eyeColor: "brown"}
];

我必须创建一个函数，您可以在其中写下一个名称，该函数可以告诉您它是否是对象数组的一部分。 有人可以帮助我吗？

Answer 1

此函数将返回firstName或lastName匹配传递的参数（搜索字符串） input ：

function filterPersons(input) {
  const results = person.filter(function(p){
    if (input.length == 0) return false;
    return (p.firstName+' '+p.lastName).match(new RegExp(input, 'i'));
  });
  return results;
};

空数组表示：没有人名或姓氏与输入字符串匹配。

该函数用于此过滤解决方案，您可以运行：

 // your input array const person = [ {firstName: "Josh", lastName: "Doe", age: 50, eyeColor: "blue"}, {firstName: "Jake", lastName: "Denver", age: 34, eyeColor: "blue"}, {firstName: "Sam", lastName: "Kiszka", age: 20, eyeColor: "brown"} ]; // the function you are looking for const filterPersons = function(input) { const results = person.filter(function(p){ if (input.length == 0) return false; return (p.firstName+' '+p.lastName).match(new RegExp(input, 'i')); }); return results; }; // this shows the filtering in action window.onload = function(){ const input = document.getElementById('val'); const output = document.getElementById('out'); input.addEventListener("keyup", function (ev) { const val = ev.target.value; // here we are calling the filter function const results = filterPersons(val); if (results.length > 0) { output.innerHTML = 'Yes! ' + JSON.stringify(results); } else { output.innerHTML ='No!'; } }); }

 <input id="val" /> <h3>included?</h3> <div id="out"> </div>

Answer 2

一种方法：

function isPartOfArrayOfObjects(person, name) {
    let found = false;

    person.forEach(entry => {
        Object.keys(entry).forEach(key => {
            if (entry[key] === name) {
                found = true;
            }
        });
    });

    return found;
}

如果您只想检查firstName和lastName值：

function isPartOfArray(person, name) {
    return person.some(entry => entry.firstName === name || entry.lastName === name);
}

Answer 3

function returnWetherNameMatch(personArr,name){
    let matched =  personArr.filter(person => {
    return person.firstName.toLowerCase() === name.toLowerCase() || person.lastName.toLowerCase() === name.toLowerCase()
  });
  if(matched.length>0) {
  return true;
  } else
    return false;
}

var person = [
{firstName: "Josh", lastName: "Doe", age: 50, eyeColor: "blue"},
{firstName: "Jake", lastName: "Denver", age: 34, eyeColor: "blue"},
{firstName: "Sam", lastName: "Kiszka", age: 20, eyeColor: "brown"}
];

var isNamePresent = returnWetherNameMatch(person,"Josh")

console.log(isNamePresent);