使用 min 函数从元组列表中获取多个元组

Question

我有一个看起来像这样的列表

mylist = [('Part1', 5, 5), ('Part2', 7, 7), ('Part3', 11, 9), ('Part4', 45, 45), ('part5', 5, 5)]

我正在寻找数字与我的输入最接近的所有元组

现在我正在使用此代码

result = min([x for x in mylist if x[1] >= 4 and x[2] >= 4])

我得到的结果是

('part5', 5, 5)

但我正在寻找一个看起来更像的结果

[('Part1', 5, 5), ('part5', 5, 5)]

如果其中有更多元组（在本例中我有 2 个，但可能更多），那么我想取回所有元组

整个代码

mylist = [('Part1', 5, 5), ('Part2', 7, 7), ('Part3', 11, 9), ('Part4', 45, 45), ('part5', 5, 5)]
result = min([x for x in mylist if x[1] >= 4 and x[2] >= 4])
print(result)

Answer 1

threshold = 4
mylist = [('Part1', 5, 5), ('Part2', 7, 7), ('Part3', 11, 9), ('Part4', 45, 45), ('part5', 5, 5)]

filtered = [x for x in mylist if x[1] >= threshold and x[2] >= threshold]
keyfunc = lambda x: x[1]
my_min = keyfunc(min(filtered, key=keyfunc))

result = [v for v in filtered if keyfunc(v)==my_min]


# [('Part1', 5, 5), ('part5', 5, 5)]