比较两个长度相同的列表并按特定值删除

Question

我有两个长度相同的列表，都有 9 个项目

listA = ["spain","italy","germany","brazil","france","argentina","peru","bolivia","giappone"]
listB = [0,0,1,1,1,0,1,1,0]

我想从 listB 中获取没有值 '1' 的 listA：

listA = ["spain", "italy","argentina","giappone"]

谢谢。

Answer 1

这是itertools.compress一个很好的用例。 不同之处在于，我们需要反转选择的二进制值，否则将是完美的使用情况:)

from itertools import compress

list(compress(listA, map(lambda x: 1-x, listB)))
# ['spain', 'italy', 'argentina', 'giappone']

或者在这种情况下，对于更简单的方法，您可以使用zip ：

[x for x,y in zip(listA,listB) if not y]
# ['spain', 'italy', 'argentina', 'giappone']

Answer 2

您可以使用zip 。

listA = ["spain","italy","germany","brazil","france","argentina","peru","bolivia","giappone"]
listB = [0,0,1,1,1,0,1,1,0]
out=[x for x,y in zip(listA,listB) if y==0]

Answer 3

listA = ["spain", "italy", "germany", "brazil",
         "france", "argentina", "peru", "bolivia", "giappone"]
listB = [0, 0, 1, 1, 1, 0, 1, 1, 0]
i = -1
for item in listB:
    i += 1
    if item == 0:
        print(listA[i])

Answer 4

只需使用zip :)

listA = ["spain", "italy", "germany", "brazil", "france", "argentina", "peru", "bolivia", "giappone"]
listB = [0, 0, 1, 1, 1, 0, 1, 1, 0]

getCountries = [i for (i,j) in zip(listA, listB) if j==0]  
'''
  i being all the countries and j being the value 0 or 1
  in this case gets all the countries only for j == 0 or you could do j != 1
'''
print(getCountries)

输出：

['spain', 'italy', 'argentina', 'giappone']