如何在循环中堆叠计算结果

Question

因此，每次我的代码循环时，我都在试图弄清楚如何将我的计算叠加起来时遇到了一些麻烦。

import java.util.Scanner;        

public class packaging {

public static void main(String[] args) {
    // TODO Auto-generated method stub

    double l = 0;
    double w = 0;
    double h = 0;

    Scanner in = new Scanner(System.in);

    System.out.println("Enter the Lenght");
    l = in.nextDouble();
    System.out.println("Enter the Lenght");
    w = in.nextDouble();
    System.out.println("Enter the Lenght");
    h = in.nextDouble();



    while (l>=5 && w>=5 && h>=5) {

        surfaceArea = 2*(l*w + w*h + l*h);
        boxCount = boxCount + 1;

    }

}        

每次while循环循环时，我都试图显示每个结果。 如果我输入长度 120 宽度 60 和高度 40 我想在每次从原始输入数字减去长度、宽度和高度时打印出结果，这意味着数字将变为 110 50 和 30 但我仍然希望结果出来出循环并打印。 有谁知道我会怎么做？

Answer 1

假设你想要的是我认为你想要的，

import java.util.Scanner;

public class packaging {

public static void main(String[] args) {
    // TODO Auto-generated method stub

    double l = 0;
    double w = 0;
    double h = 0;
    double boxCount = 0;
    double surfaceArea = 0;
    Scanner in = new Scanner(System.in);

    System.out.println("Enter the Lenght");
    l = in.nextDouble();
    System.out.println("Enter the Lenght");
    w = in.nextDouble();
    System.out.println("Enter the Lenght");
    h = in.nextDouble();



    while (l>=5 && w>=5 && h>=5) {

        surfaceArea = 2*(l*w + w*h + l*h);

        boxCount = boxCount + 1;
        l = l - 10;
        w = w - 10;
        h = h - 10;

        System.out.println("The box count is "+ boxCount);
        System.out.println("The surface Area is "+ surfaceArea);
    }
    in.close();
}

样本输出

Enter Length
15
Enter Length
20
Enter Length
30
The Box count is 1
The Surface Area is [CALCULATED_VALUE]
The Box count is 2
The Surface Area is [CALCULATED_VALUE]
The Box count is 3
The Surface Area is [CALCULATED_VALUE]

这将在每次循环运行时打印 boxCount 和 surfaceArea。 希望这是您想要的，如果不是，请添加更多信息，我很乐意为您提供帮助。

Answer 2

只需将打印语句移动到循环体内即可。

while(...) {
  ...
  System.out.println("The box count is "+ boxCount);
  System.out.println("The surface Area is "+ surfaceArea); 
}