如何使用 Groovy 删除仅包含数字的 xml 标记

Question

我有以下 XML 示例：

<?xml version="1.0" encoding="UTF-8" ?>
<0>
    <user>
        <fname>bob</fname>
        <lname>marley</lname>
        <age>30</age>
    </user>
</0>
<1>
    <user>
        <fname>john</fname>
        <lname>lennon</lname>
        <age>20</age>
    </user>
</1>
<2>
    <user>
        <fname>phil</fname>
        <lname>smith</lname>
        <age>40</age>
    </user>
</2>

我想最终只有用户......就像这样......

    <user>
        <fname>bob</fname>
        <lname>marley</lname>
        <age>30</age?
    </user>
    <user>
        <fname>john</fname>
        <lname>lennon</lname>
        <age>20</age>
    </user>
    <user>
        <fname>phil</fname>
        <lname>smith</lname>
        <age>40</age>
    </user>

我已经使用正则表达式去掉了 XML 声明行……但是现在我需要删除整数标签并只获取 USER 标签

这是我到目前为止。 我被正则表达式部分绊倒了..（我想！）

String x1 = '''
<?xml version="1.0" encoding="UTF-8" ?>
<0>
    <user>
        <fname>bob</fname>
        <lname>marley</lname>
        <age>30</age>
    </user>
</0>
<1>
    <user>
        <fname>john</fname>
        <lname>lennon</lname>
        <age>20</age>
    </user>
</1>
<2>
    <user>
        <fname>phil</fname>
        <lname>smith</lname>
        <age>40</age>
    </user>
</2>
'''

import java.util.regex.Pattern

//remove the XML declaration
String x2 = x1.replaceAll("\\<\\?xml(.+?)\\?\\>", "").trim();

//grab the opening XML tag --- not quite sure how to insert dynamic REGEX here
String openingNumberTag = "<" + "[0-9]+" + ">";

//grab the closing XML tag --- not quite sure how to insert dynamic REGEX here
String closingNumberTag = "</" + "[0-9]+" + ">";

//Now iterate through the XML string and remove the number tags
if (x2.matches(openingNumberTag))
{
    //remove it somehow;                     
}
if (x2.matches(closingNumberTag))
{
    //remove it somehow;                     
}

//Print the final XML string with just the USER tags
println(x2);

任何帮助表示感谢

Answer 1

我就这样解决了......

String x1 = '''
<?xml version="1.0" encoding="UTF-8" ?>
<0>
    <user>
        <fname>bob</fname>
        <lname>marley</lname>
        <age>30</age>
    </user>
</0>
<1>
    <user>
        <fname>john</fname>
        <lname>lennon</lname>
        <age>20</age>
    </user>
</1>
<2>
    <user>
        <fname>phil</fname>
        <lname>smith</lname>
        <age>40</age>
    </user>
</2>
'''

import java.util.regex.Pattern

//remove the XML declaration
String x2 = x1.replaceAll("\\<\\?xml(.+?)\\?\\>", "").trim();
String x3 = x2.replaceAll("<[0-9]+>", "").trim();
String x4 = x3.replaceAll("</[0-9]+>", "").trim();


println(x4);