列出 Python 中超出范围的索引（IF 语句）

Question

我在搞乱，这是我的代码的“错误”部分，我认为您没有必要了解更多：

def parse(toks):
    i = 0
    while(i < len(toks)):
        if toks[i] + " " + toks[i+1][0:6] == "CMD_SHOW STRING" or toks[i] + " " + toks[i+1][0:3] == "CMD_SHOW NUM" or toks[i] + " " + toks[i+1][0:4] == "CMD_SHOW EXPR":
            if toks[i+1][0:6] == "STRING":
                doPRINT(toks[i+1])

            elif toks[i+1][0:3] == "NUM":
                doPRINT(toks[i+1])

            elif toks[i+1][0:4] == "EXPR":
                doPRINT(toks[i+1])

            i += 2

        if toks[i][0:3] + " " + toks[i+1] + " " + toks[i+2][0:6] == "VAR EQUALS STRING" or toks[i][0:3] + " " + toks[i+1] + " " + toks[i+2][0:3] == "VAR EQUALS NUM" or toks[i][0:3] + " " + toks[i+1] + " " + toks[i+2][0:4] == "VAR EQUALS EXPR":
            if toks[i+2][0:6] == "STRING":
                doASSIGN(toks[i], toks[i+2])

            elif toks[i+2][0:3] == "NUM":
                doASSIGN(toks[i], toks[i+2])

            elif toks[i+2][0:4] == "EXPR":
                doASSIGN(evalExpression(toks[i], toks[i+2]))

            i += 3

我收到此错误：

Traceback (most recent call last):
  File "C:\Users\Kuba\Desktop\Programowanie\Projekty\Amai\amailexparse.py", line
 135, in parse
    if toks[i][0:3] + " " + toks[i+1] + " " + toks[i+2][0:6] == "VAR EQUALS STRI
NG" or toks[i][0:3] + " " + toks[i+1] + " " + toks[i+2][0:3] == "VAR EQUALS NUM"
 or toks[i][0:3] + " " + toks[i+1] + " " + toks[i+2][0:4] == "VAR EQUALS EXPR":
IndexError: list index out of range

我尝试了很多事情，改变 i 的值，改变数组大小，减少语句。 谁能帮我这个？ 这是我的在线学校项目，所以我需要快速帮助。

Answer 1

要解决此问题，您可以将循环的 while 循环条件更改为以下内容：

while( (i+2) < len(toks) )