JSON 字符串里面的变量

Question

我正在开发一个制作简历的应用程序，我有一个 JSON 文件，其中包含用户可以选择的职位描述。 问题是用户飞行的飞机可能很多，我想添加一个变量，我可以在 JSON 字符串中更改。 是这样的：

{
"data":[
  {
    "jobDescription": "Worldwide Passenger and freighter flights in all weather conditions, on the modern " + yourAirplane + ". I Have gained experience flying to destinations in all continents while working with different nationalities"
  }
 ]
}

我一直在谷歌搜索，但找不到任何东西。 我用以下代码解析字符串：

struct  JobDescriptionData : Decodable{
    var data:[JobDescritpion]?
}

class JobDescritpion:  NSObject, Decodable {

    static let shared = JobDescritpion()

    var jobDescription : String?

    func loadJobDescriptions(completion: ([JobDescritpion]) -> ()){
        let path = Bundle.main.path(forResource: "jobDescription", ofType: "json")!
                do {
                    let data = try Data(contentsOf: URL(fileURLWithPath: path), options: .mappedIfSafe)
                    data.printJSON()
                    let decoder = JSONDecoder()
                    guard let eventResult = try? decoder.decode(JobDescriptionData.self, from: data) else { return }

                    var array = [JobDescritpion]()
                    array = eventResult.data!
                    completion(array)

                    } catch {
                }
    }
}

printJSON() （这是我对 Data 的扩展，用于打印 json 数组）有效并返回数组，但当然，守卫 let 失败，因为jobDescription不是字符串。

关于如何添加变量然后稍后在应用程序中设置它的任何建议？

Answer 1

为您的 JSON 使用字符串格式

例子

let stringTemplate = "Worldwide Passenger and freighter flights in all weather conditions, on the modern %@. I Have gained experience flying to destinations in all continents while working with different nationalities"

let formattedString = String(format: stringTemplate , "some value")
print(formattedString)

Answer 2

将 JSON 保留为字符串：

{
    "data": [{
        "jobDescription": "Worldwide Passenger and freighter flights in all weather conditions, on the modern <yourAirplane>. I Have gained experience flying to destinations in all continents while working with different nationalities"
    }]
}

解码后：

"description".replacingOccurrences(of: "<yourAirplane>", with: yourAirplane)