使用 pdfminer.six 从 URL 打开 PDF

Question

背景：Python 3.7 & pdfminer.six

使用此处找到的信息： Exporting Data from PDFs with Python ，我有以下代码：

import io

from pdfminer.converter import TextConverter
from pdfminer.pdfinterp import PDFPageInterpreter
from pdfminer.pdfinterp import PDFResourceManager
from pdfminer.pdfpage import PDFPage

def extract_text_from_pdf(pdf_path):
    resource_manager = PDFResourceManager()
    fake_file_handle = io.StringIO()
    converter = TextConverter(resource_manager, fake_file_handle)
    page_interpreter = PDFPageInterpreter(resource_manager, converter)

    with open(pdf_path, 'rb') as fh:
        for page in PDFPage.get_pages(fh, 
                                      caching=True,
                                      check_extractable=True):
            page_interpreter.process_page(page)

        text = fake_file_handle.getvalue()

    # close open handles
    converter.close()
    fake_file_handle.close()

    if text:
        return text

if __name__ == '__main__':
    path = '../_pdfs/mypdf.pdf'
    print(extract_text_from_pdf(path))

这可行（耶，），但我真正想做的是通过 url 直接请求 pdf。 而不是打开已预先保存到本地驱动器的 pdf。

我不知道如何修改“打开”逻辑以从远程 url 调用，我也不确定哪个请求库最适合用于最新版本的 Python（请求、urllib、urllib2 等？ )

我是 Python 的新手，所以请记住这一点（Ps 我发现了其他关于此的问题，但我无能为力 - 可能是因为它们往往很旧。）

任何帮助将不胜感激！ 谢谢！

Answer 1

我解决了如下：

from io import StringIO, BytesIO
import urllib.request

from pdfminer.converter import TextConverter
from pdfminer.pdfinterp import PDFPageInterpreter, PDFResourceManager
from pdfminer.pdfpage import PDFPage

def extract_text_from_pdf_url(url, user_agent=None):
    resource_manager = PDFResourceManager()
    fake_file_handle = StringIO()
    converter = TextConverter(resource_manager, fake_file_handle)    

    if user_agent == None:
        user_agent = 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/83.0.4103.61 Safari/537.36'

    headers = {'User-Agent': user_agent}
    request = urllib.request.Request(url, data=None, headers=headers)

    response = urllib.request.urlopen(request).read()
    fb = BytesIO(response)

    page_interpreter = PDFPageInterpreter(resource_manager, converter)

    for page in PDFPage.get_pages(fb,
                                caching=True,
                                check_extractable=True):
        page_interpreter.process_page(page)


    text = fake_file_handle.getvalue()

    # close open handles
    fb.close()
    converter.close()   
    fake_file_handle.close()

    if text:
        # If document has instances of \xa0 replace them with spaces.
        # NOTE: \xa0 is non-breaking space in Latin1 (ISO 8859-1) & chr(160)
        text = text.replace(u'\xa0', u' ')

        return text

Answer 2

您可以使用PyPDF2解析 pdf 文件。
尝试这个：

import requests, PyPDF2
# Fill address with your url
try:
    response = requests.get(address)
except:
    print("Error")
my_raw_data = response.content
with open("my_pdf.pdf", 'wb') as my_data:
    my_data.write(my_raw_data)
my_data.close()
open_pdf_file = open("my_pdf.pdf", 'rb')
try:
    read_pdf = PyPDF2.PdfFileReader(open_pdf_file)
except:
    print("Failed to read, Press Enter to continue :")
if read_pdf.isEncrypted:
    read_pdf.decrypt("")
n = read_pdf.getNumPages()
for x in range(0,n):
    try:
        s = read_pdf.getPage(x).extractText()
    except:
        print("Error in",i)
        continue
    print(s)

Answer 3

从 url 中检索 pdf 的更简单的解决方案是：

def pdf_getter(url:str):
    '''
    retrives pdf from url as bytes object
    '''
    open = urllib.request.urlopen(url).read()
    return io.BytesIO(open)

PDFParser() function 和高级 extract_text() function 都将接受返回的 object 作为输入。