无法将关键字“用户名”解析为字段。 选项有：bio、blog、description、id、image、speciality、status、user、user_id

Question

嘿，我想为我的用户创建一个个人资料页面，当人们登录网站时，他们可以查看每个用户的个人资料，每当我尝试登录到我得到的用户的每个个人资料时，我都会收到上述错误，这是我下面的代码

视图.py

class DoctorDetailView(LoginRequiredMixin, DetailView):
    model = Doctor
    fields = ['user', 'email', 'image', 'speciality', 'bio']
    template_name = 'pages/doctor_detail.html'

    def get_queryset(self):
        user = get_object_or_404(Doctor, username=self.kwargs.get('username'))
        return Doctor.objects.filter(doctor=user.doctor)

网址.py

    path('doctor/', doctor, name='doctor'),
    path('doctor/info/<str:username>', user_views.DoctorDetailView.as_view(), name='doctor-detail'),

医生.html

<a href="{% url 'doctor-detail' doc.user.username %}"><div class="img-wrap d-flex align-items-stretch">
                                <div class="img align-self-stretch" style="background-image: url({{ doc.user.doctor.image.url }}"></div>

模型.py

class CustomUser(AbstractUser):
    is_doctor = models.BooleanField(default=False)

    def __str__(self):
        return self.email


class Status(models.Model):
    title= models.CharField(max_length=5)


    def __str__(self):
        return self.title


class Doctor(models.Model):
    user = models.OneToOneField(CustomUser, on_delete=models.CASCADE, null=True, related_name="doctor")
    image = models.ImageField(default='jazeera.jpg', upload_to='profile_pics')
    bio = models.TextField()
    speciality = models.CharField(max_length=300)
    describtion = models.CharField(max_length=100)
    status = models.ManyToManyField(Status)

Answer 1

Doctor object 没有用户名，因此：

user = get_object_or_404(Doctor, username=self.kwargs.get('username'))

没有多大意义，但是您不需要先使用get_object_or_404来获取用户，您可以过滤：

from django.shortcuts import get_object_or_404

class DoctorDetailView(LoginRequiredMixin, DetailView):
    model = Doctor
    fields = ['user', 'email', 'image', 'speciality', 'bio']
    template_name = 'pages/doctor_detail.html'

    def get_object(self):
        return get_object_or_404(Doctor, user__username=self.kwargs['username'])