[英]File handling in java misunderstanding
嗨,我目前正在学习Java,我在Java中阅读了很多关于文件处理的内容,但我还不明白。
import java.math.BigInteger;
import java.util.Scanner;
public class multiply {
public static void main(String []args) {
Scanner cin = new Scanner(System.in); // Create a Scanner object
String firstNumber = "";
int n = cin.nextInt();
while (n != 0) {
int number = cin.nextInt();
firstNumber = firstNumber + number;
n--;
}
BigInteger number1 = new BigInteger(firstNumber);
String firstNumber2 = "";
int n2 = cin.nextInt();
while (n2 != 0) {
int number2 = cin.nextInt();
firstNumber2 = firstNumber2 + number2;
n2--;
}
BigInteger number2 = new BigInteger(firstNumber2);
//BigInteger res = new BigInteger(number1.multiply(number2));
System.out.println(number1.multiply(number2));
}
}
我想出了这个程序,它乘以大 integer 但是,我不知道我应该添加什么以便它从名为“multiply.in”的文件中读取,并将结果显示在文件“multiply.out”中。
在c++中,我知道使用ifstream,ofstream可以解决问题。
如果您能帮助我编写代码,将不胜感激。
此代码读取文件并仅从第一行获取 integer 值。 并执行诸如加法和乘法之类的操作以及写入文件。
public static void main(String args[]) throws IOException {
Scanner cin = new Scanner(System.in); // Create a Scanner object
File file = new File("/home/Downloads/multiplyin.txt");
File fileOut = new File("/home/Downloads/multiplyOut.txt");
BufferedReader reader = new BufferedReader(new FileReader(file));
String firstNumber = reader.readLine();
System.out.println("input 1");
int n = cin.nextInt();
System.out.println("input 2");
int n2 = cin.nextInt();
while (n != 0) {
System.out.println("sub inputs" + n);
int number = cin.nextInt();
firstNumber = firstNumber + number;
n--;
}
BigInteger number1 = new BigInteger(firstNumber);
while (n2 != 0) {
System.out.println("sub inputs" + n);
int number2 = cin.nextInt();
firstNumber = firstNumber + number2;
n2--;
}
BigInteger number2 = new BigInteger(firstNumber);
BufferedWriter writer = new BufferedWriter(new FileWriter(fileOut));
writer.write(String.valueOf(number1.multiply(number2)));
writer.close();
reader.close();
}
}
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