最小和最大游戏数之间的差异

Question

问题：显示所有具有以下条件的玩家的姓名：该玩家的最小和最大游戏数之差大于 5。

select p.name
from player p
join competition c
on c.playerID = p.playerID
where (
(select count(*) from competition
 where count(games) > 1
 group by playerID
) - (
select count(*) from competition
  where count(games) <= 1
  group by playerID
))> 5;

我有点迷路了。 我不太确定这是正确的方法，我应该如何进行：我应该使用count并找到最小和最大游戏数并与大于 5 进行比较，还是应该使用count 、 min和max函数。 非常感谢，如果有人能解释一下这个逻辑。

表：

player       competition
-------      --------
playerID     playerID
name         games
birthday     date
address      
telefon

Answer 1

SELECT 
P.Name,
MIN(C.Games) MinGame,
MAX(C.Games) MaxGame,
FROM Player P
INNER JOIN Competition C
ON C.PlayerId = P.PlayerId
GROUP BY P.Id, P.Name
HAVING MAX(C.Games) -  MIN(C.Games)  > 5

Answer 2

它应该是一个简单的查询：

With tab1 AS (Select player.name, min(games) mx_game, max(games) min_game,
max(games) - min(games) diff
from player JOIN competition ON player.player_id = competition.id
group by player.player_id, player.name)

Select tab1.name from tab1
WHERE diff >5;

我在组中添加 player_id，因为 player_name 可能与 2 人相似。