如何在同一行中对多个依赖项进行分组 - Gradle

Question

在下面的示例中，我有 3 个具有相同组和相同版本的依赖项。 我想将这三个依赖项归为一行。

compile group: 'org.apache.ws.commons.axiom', name: 'axiom-api', version: '1.2.7'
compile group: 'org.apache.ws.commons.axiom', name: 'axiom-dom', version: '1.2.7'
compile group: 'org.apache.ws.commons.axiom', name: 'axiom-impl', version: '1.2.7'

预期如下

group("axiom-api", "axiom-dom", "axiom-impl", :under=>"org.apache.ws.commons.axiom", :version=>"1.2.7")

gradle有可能吗？

Answer 1

好吧，实际上总共有更多的行，但如果这（相同的组、相同的版本和多个工件）是一个重复模式，它可能仍然很方便：

def groupDependencies ( group, names, version ) {
  def deps = []
  names.each { it -> 
    deps += [group: group, name: it, version: version]
  }

  return deps
}

dependencies {
  compile(groupDependencies('org.apache.ws.commons.axiom', ['axiom-api', 'axiom-dom', 'axiom-impl'], '1.2.7'))
}

Answer 2

这是一个示例，您可以在其中添加不同版本的不同工件。

def groupDependencies (group, artifact) {
    def dependencies = []

    artifact.each { it ->
        dependencies += [group: group, name: it["name"], version: it["version"]]
    }

    return dependencies
}

dependencies {
    implementation(groupDependencies("org.apache.commons", [
            [name: "commons-lang3", version: "3.12.0"],
            [name: "commons-collections4", version: "4.4"],
            [name: "commons-compress", version: "1.21"]
    ]))
}

另一个是当组和名称相同时（你可以在同一个文件中使用它们）：

def groupDependencies (artifact) {
    def dependencies = []

    artifact.each { it ->
        dependencies += [group: it["name"], name: it["name"], version: it["version"]]
    }

    return dependencies
}

dependencies {
    implementation(groupDependencies([
            [name: "commons-cli", version: "1.5.0"],
            [name: "commons-io", version: "2.11.0"]
    ]))
}