关于服务器版本的MySQL语法错误的解决方法？

Question

我对 SQL 语法有疑问。 我有一个查询，但收到错误 1064。我尝试了一些不同的方法，但找不到正确的解决方案。 这是我的查询：

 $sql = "SELECT id FROM
                (SELECT id, category_id, @row_number := IF(@prev = category_id, @row_number + 1, 1) AS row_number, @prev := category_id
                FROM posts
                JOIN (SELECT @prev := NULL, @row_number := 0) AS vars
                WHERE posts.is_scheduled = 0 AND posts.visibility = 1 AND posts.status = 1
                ORDER BY category_id, created_at DESC
                ) AS table_posts
                WHERE row_number <= 10";

我得到的错误是：

错误编号：1064

您的 SQL 语法有错误； 检查与您的 MySQL 服务器版本相对应的手册，了解在第 2 行的“row_number, @prev := category_id FROM posts JOIN”附近使用的正确语法

SELECT id FROM (SELECT id, category_id, @row_number := IF(@prev = category_id, @row_number + 1, 1) AS row_number, @prev := category_id FROM posts JOIN (SELECT @prev := NULL, @row_number := 0) AS vars WHERE posts.is_scheduled = 0 AND posts.visibility = 1 AND posts.status = 1 ORDER BY category_id, created_at DESC ) AS table_posts WHERE row_number <= 10

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