查找文本中的所有数字并将它们返回到 python 中的浮点数列表中

Question

我有文本摘录，需要创建一个函数来查找文本中的所有数字并在浮点数列表中返回它们。

如果可以用逗号分隔千位，并且可以用逗号和空格分隔几个连续的数字，那就太好了

E.g., extract_numbers("12 days of XMas") is [12.0]
E.g., extract_numbers("1, 2, 3, un pasito pa'lante Maria")
is [1.0, 2.0, 3.0]

:param text: string that forms English text
:return: list of numbers (as floats) that are present in the text
:rtype: list

  #Variable for storing the sum 
a = 0
  
 #Iterating through the content 
 #Of the file 
for line in content: 
      for i in line: 
          
        # Checking for the digit in  
        # the string 
        if i.isdigit() == True: 
              
            a += int(i) 
  
[float(i) for i in a]
print("The sum is:", a)

不幸的是，我收到了一个 TypeError ：

'int' object is not iterable' at '[float(i) for i in a]'

Answer 1

a是 int 并且它不可迭代。 你可以使用这个：

a = 0
floats = []  
for line in content: 
      for i in line: 
        if i.isdigit() == True:              
            a += int(i) 
            floats.append(float(i))

现在floats是一个包含所有数字的列表。

Answer 2

使用正则表达式，您的extract_numbers函数可能如下所示：

import re

def extract_numbers(line):
  return [float(num) for num in re.findall(r'\d+', line)]

那么你可以进行以下操作：

# Variable for storing the sum 
a = 0

# Iterating through the content of the file 
for line in content: 
    a += extract_numbers(line)

print("The sum is:", a)