[英]Looping mysqli update with variable increasing by 1 in while loop
我正在尝试循环此代码,因为它将动态生成。 它从 mysql 获取行数并循环多次。 POST 来自 ajax,它也在那里循环并且运行良好。 在 php 部分,我不确定为什么它不起作用。 我尝试了很多不同的循环变化。
$queryEle = "SELECT * FROM featureSheetContent WHERE `user_id` = '$userID' AND `feature_id` = '$featureID'";
$resultEle = mysqli_query($connect,$queryEle);
$rowEle = mysqli_num_rows($resultEle);
$i = 1;
while ($i < $rowEle) {
$eleID.$i = $_POST['eleID'.$i];
$eleID .= $eleID.$i;
$resizeWidth.$i = $_POST['resizeWidth'.$i];
$resizeWidth .= $eleID.$i;
$resizeHeight.$i = $_POST['resizeHeight'.$i];
$resizeHeight .= $eleID.$i;
$UploadMain = $connect->prepare("UPDATE featureSheetContent SET `ele_width` = ?, `ele_height` = ? WHERE id = ?");
$UploadMain->bind_param('sss', $resizeWidth, $resizeHeight, $eleID);
$UploadMain->execute();
$i++;
}
未循环代码有效:
$eleID1 = $_POST['eleID1'];
$resizeWidth1 = $_POST['resizeWidth1'];
$resizeHeight1 = $_POST['resizeHeight1'];
$eleID2 = $_POST['eleID2'];
$resizeWidth2 = $_POST['resizeWidth2'];
$resizeHeight2 = $_POST['resizeHeight2'];
$UploadMain = $connect->prepare("UPDATE featureSheetContent SET `ele_width` = ?, `ele_height` = ? WHERE id = ?");
$UploadMain->bind_param('sss', $resizeWidth1, $resizeHeight1, $eleID1);
$UploadMain->execute();
$UploadMain = $connect->prepare("UPDATE featureSheetContent SET `ele_width` = ?, `ele_height` = ? WHERE id = ?");
$UploadMain->bind_param('sss', $resizeWidth2, $resizeHeight2, $eleID2);
$UploadMain->execute();
您的变量变量语法错误; 正确的语法是${"eleID".$i}
。 但是没有必要在循环中每次都使用不同的变量。 将UPDATE
查询绑定到一组特定的变量,并从POST
变量中重新分配这些变量。
$eleID = $resizeWidth = $resizeHeight = null; // Create the variables before binding
$UploadMain = $connect->prepare("UPDATE featureSheetContent SET `ele_width` = ?, `ele_height` = ? WHERE id = ?");
$UploadMain->bind_param('sss', $resizeWidth, $resizeHeight, $eleID);
for ($i = 1; $i <= $rowEle; $i++) {
$eleID = $_POST['eleID'.$i];
$resizeWidth = $_POST['resizeWidth'.$i];
$resizeHeight = $_POST['resizeHeight'.$i];
$UploadMain->execute();
}
顺便说一句,您的UPDATE
查询将为任何用户更新一行,而不仅仅是user_id = '$userID'
。 这是故意的吗?
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