多组mongodb聚合怎么办

Question

我需要获取所有文件并计算所有 RejectionCause + SubRejectionCause。

在某些文档中，我没有SubRejectionCause ，因为它使小组搞砸了。

需要的结果是：

[{
  RejectionCause : 1,
  sum: 1,
  SubRejectionCause: [SubRejectionCause: 3,sum: 1,]...
}]

蒙戈文件

{
    "_id" : ObjectId("5fd62b3ea6f33c88cd000cab"),

    "CampaignCode" : "TEST",
    "UpdateDate" : ISODate("2018-10-31T22:00:00.000Z"),
    "CreateDate" : ISODate("2018-10-31T22:00:00.000Z"),
    "Status" : "Rejection",
    "RejectionCause" : {
        "RejectionCause" : "2",
        "SubRejectionCause" : "14",

    },
}

.aggregate([
            {
                $match: {'CreateDate': { $gte: ISODate("2015-08-31T21:00:00.000Z"), $lte: ISODate("2020-08-31T21:00:00.000Z")}},
            },
            {
                $group: {
                    "_id": { CampaignCode: "$CampaignCode", RejectionCause: "$RejectionCause.RejectionCause", SubRejectionCause: "$RejectionCause.SubRejectionCause"},
                    count: { $sum: 1 }
                }
            },
            {
                $group: {
                    "_id": { CampaignCode: "$_id.CampaignCode", RejectionCause: "$_id.RejectionCause.RejectionCause"},
                    "SubRejectionStatus": {
                        $push : {
                            RejectionCause: "$_id.SubRejectionCause",
                            count: "$count",
                        },
                    },
                    count: { $sum: "$count" }
                }
            },
            {
                $group : {
                    "_id": { CampaignCode: "$_id.CampaignCode"},
                    "CountByStatus": {
                        $push : {
                            RejectionCause: "$_id.RejectionCause",
                            count: "$count",
                            SubRejectionStatus: "$SubRejectionStatus"
                        },
                    },
                    "total": { "$sum": "$count" }
                }
            }])