使用 CYPHER 读取 json 中的 json 属性名称

Question

我的 Neo4J 数据库有这种输入 JSON 文件：

    {"list":[
    {
      "extraction":{"extractorId":"45485","date":"20211201","location":"France"},
      "actors":{"88187":"Toto","74017":"Titi","78901":"Tata","45867":"Tutu"},
      "data":{"2877:-99033:-979":{"4934":[45867],"4935":[88187],"4933":[74017],"4932":[45867],"4931":[78901,45867],"4930":[78901]}}
    },

    {"extraction":{"extractorId":"45485","date":"20211201","location":"England"},
     "actors":{"42815":"Lala","45867":"Tutu"},
     "data":{"2877:-99033:-979":{"4939":[86970],"4934":[74975,45867],"4935":[42815,88187],"4933":[74017],"4932":[45867],"4931":[78901,45867],"4930":[78901]}}}
    ]}

如您所见，这不是标准的 JSON 格式，因为属性名称也可以是值。

如何使用 UNWIND、FOREACH 等阅读此内容？ 单行 CYPHER 请求不是强制性的。

例如，如果我想用 (a:Actor {id,name}) 创建节点，如果我尝试这个：

WITH "file:///data.json" as json
CALL apoc.load.json(json) YIELD value
UNWIND value.list AS item
UNWIND item.actors AS actors
RETURN actors

我明白了

row1 :
{
  "45867": "Tutu",
  "74017": "Titi",
  "78901": "Tata",
  "88187": "Toto"
}
row 2 : 
{
  "42815": "Lala",
  "45867": "Tutu",
}

如何获取 ID 和名称以在 MERGE 节点 cypher 命令中使用它们？

Answer 1

keys function 可以在这里提供帮助。 详细说明您的初始查询：

WITH "file:///data.json" as json
CALL apoc.load.json(json) YIELD value
UNWIND value.list AS item
UNWIND item.actors AS actors
// Extract map's keys, that will be the ID
WITH keys(actors) as keys, actors
// "loop" over keys
UNWIND keys as key
RETURN key as id, actors[key] as name

结果：

╒═══════╤══════╕
│"id"   │"name"│
╞═══════╪══════╡
│"78901"│"Tata"│
├───────┼──────┤
│"45867"│"Tutu"│
├───────┼──────┤
│"74017"│"Titi"│
├───────┼──────┤
│"88187"│"Toto"│
├───────┼──────┤
│"45867"│"Tutu"│
├───────┼──────┤
│"42815"│"Lala"│
└───────┴──────┘