如何使用两个输入 model 将多个参数传递给 API

Question

我试图将参数传递给两个不同的输入 model 并且当我传递参数时，我只能传递一个输入 model 而另一个返回我 null 值。 我在我的 API 中使用了 XML，这就是为什么我需要将输入 model 分成两个。 任何人都知道如何使参数通过 List < AddARInvoiceDetail> 详细信息？

ARInvoice.aspx.cs

[WebMethod]
        public static string AddARInvoice(iAddARInvoice iAddARInvoice, iAddARInvoiceDetail iAddARInvoiceDetail)
        {
            var body_object = JsonConvert.SerializeObject(new
            {
               
                RefNo = iAddARInvoice.RefNo,
                FootNotes = iAddARInvoice.FootNotes,
                FootSubAmt = iAddARInvoice.FootSubAmt,
                FootDiscountAmt = iAddARInvoice.FootDiscountAmt,
                FootTaxAmt = iAddARInvoice.FootTaxAmt,
                FootTotalAmt = iAddARInvoice.FootTotalAmt,


                ItemCode = iAddARInvoiceDetail.ItemCode,
                ItemName = iAddARInvoiceDetail.ItemName,

            });
            oResult response = Util.PostApi(body_object, "invoice/AddARInvoice");

            if (!response.StatusCode)
                return PopupMsg(RESOURCE.Label("MsgSaveFailed", response.Message), false);

            returnPopupMsg(RESOURCE.Label("MsgAddProfileSuccess"), true);
        }

iAddARInvoice.cs（输入 model 1）

public class iAddARInvoice
{
    public iAddARInvoice()
    {
      RefNo = "";
      FootNotes = "";
      FootSubAmt = 0;
      FootDiscountAmt = 0;
      FootTaxAmt = 0;
      FootTotalAmt = 0;
      
   }

   public string RefNo { get; set; }
   public string InvoiceDueDate { get;set;}
   public string FootNotes { get;set;}
   public double FootSubAmt { get; set; }
   public double FootDiscountAmt { get;set;}
   public double FootTaxAmt { get; set; }
   public double FootTotalAmt { get;set;}


   public List<iAddARInvoiceDetail> detail { get; set; }
}

iAddARInvoiceDetail.cs（输入 model 2）

public class iAddARInvoiceDetail
     {
            public iAddARInvoiceDetail()
            {
                ItemCode = "";
                ItemName = "";
            }
     
            public string ItemCode { get; set; }
            public string ItemName { get; set; }
        }

我在使用 quickwatch 运行时得到的结果

RefNo: 0001,
FootNotes: testing,
FootSubAmt: 20.00,
FootDiscountAmt:0.00,
FootTaxAmt:0.00,
FootTotalAmt:20.00,
detail: null   //suppose here it should return me count=1 because it pass to the List<iAddARInvoiceDetail>