
[英]How to fetch specific elements from an array and create a new array based on the comparison of an array key's value?
[英]How to dynamically create a new array based on a specific value with a loop PHP
例如,我有一个这样的数组:
$a1=array("U001","U002");
/*
Output:
Array (
[0] => U001
[1] => U002
)
*/
我想创建一个新数组,其元素数量基于一个值,例如,如果值为 2,则数组变为:
$values: 2
$a1=array("U001","U002");
$newArr=array("U001","U001","U002","U002");
/*
Output:
Array (
[0] => U001
[1] => U001
[2] => U002
[3] => U002
)
*/
此外,如果数组本身由 3 组成,并且值为 3,则:
$values: 3
$a1=array("U001","U002","U003");
$newArr=array("U001","U001","U001","U002","U002","U002","U003","U003","U003");
/*
Output:
Array (
[0] => U001
[1] => U001
[2] => U001
[3] => U002
[4] => U002
[5] => U002
[6] => U003
[7] => U003
[8] => U003
)
*/
如何创建动态 function 来创建这个新数组? 我正在考虑添加一个 if-else,但我不知道如何在循环过程中使用它..
谢谢你的帮助
好像您正在合并多个数组。 您可以使用array_merge
。
$a = ["a", "b"];
$b = ["c", "d"];
$c = array_merge($a, $b);
print_r($c);
//Output:
/*
Array
(
[0] => a
[1] => b
[2] => c
[3] => d
)
*/
尝试这个
$a1=["U001","U002"];
$values = 5;
$newArray = [];
foreach($a1 as $item) {
for ($i= 0; $i < $values; $i++) {
$newArray[] = $item;
}
}
所以就像凯文在评论中建议的那样,代码就是这样
$a1=array("U001","U002");
foreach($a1 as $x) {
for ($i=0; $i < count($a1); $i++) {
echo $x. "</BR>";
}
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