SQLite 3 用 python 3.8 更新表中的行

Question

目前我有一个从以下代码创建的数据库：

import sqlite3

#Create connection and cursor.

connection = sqlite3.connect('impacts')

cursor = connection.cursor()

command1 = """CREATE TABLE IF NOT EXISTS
projects(project_id INTEGER PRIMARY KEY, project_type TEXT, project_LID TEXT, risks_assumptions BLOB)"""

cursor.execute(command1)

command2 = """CREATE TABLE IF NOT EXISTS
project_details(project_code TEXT PRIMARY KEY, project_id INTEGER, project_name TEXT, project_manager TEXT,
FOREIGN KEY(project_id) REFERENCES projects(project_id))"""

cursor.execute(command2)

command3 = """CREATE TABLE IF NOT EXISTS
role_impacts(impact_id INTEGER PRIMARY KEY, project_id INTEGER, project_impact INTEGER, project_role TEXT,
FOREIGN KEY(project_id) REFERENCES projects(project_id))"""

cursor.execute(command3)

command4 = """CREATE TABLE IF NOT EXISTS
project_story(story_id INTEGER PRIMARY KEY, project_id INTEGER, project_story TEXT,
FOREIGN KEY(project_id) REFERENCES projects(project_id))"""

cursor.execute(command4)

command5 = """CREATE TABLE IF NOT EXISTS
project_logins(user_name TEXT PRIMARY KEY, user_pass TEXT, user_access INTEGER)"""

cursor.execute(command5)

在一个单独的程序中，我正在与该数据库进行交互，但是每当我尝试更新数据库时，它由于某种原因无法正常工作。

这是从表中选择所有记录的代码，它可以正确获取它们：

def selectLogins():
    connection = sqlite3.connect('impacts')
    cursor = connection.cursor()
    cursor.execute("SELECT * FROM project_logins")
    results = cursor.fetchall()
    print (results)

然后这是我更新登录的代码，它没有像我期望的那样更新“BEN”记录：

def updateLogins():
    connection = sqlite3.connect('impacts')
    cursor = connection.cursor()  
    cursor.execute("UPDATE project_logins SET user_pass = '5678' WHERE user_name = 'BEN'")
    cursor.execute("SELECT * FROM project_logins WHERE user_name = 'BEN'")
    results = cursor.fetchall()
    print (results)
    connection.commit()

sqlite 3 和 python 中的数据库的新手，所以任何关于为什么这不起作用或我通常可以做得更好的建议将不胜感激。