我如何保持 turtle.Screen() 运行并接受命令移动/转动海龟？

Question

我正在尝试以我的风格制作 LOGO 的复制版本（对我来说轻松一点）。 与 LOGO 非常相似（但不太相似），我想继续在 powershell 中输入并同时查看屏幕上的变化。 但是在这段代码中，屏幕只是打开了，就是这样，没有输入提示。 帮我。 这是代码：

#----------------
# turtle paint
#----------------

import turtle


def main():
    
    bg_color = input("What backgroud color would you like?")    # taking input for bg_color
    tur_color = input("What color of turtle will you like?")

    wn = turtle.Screen()        # creates a screen for turtle drawing
    wn.bgcolor(bg_color)
    tur = turtle.Turtle()           # tur is assigned Turtle
    
    move()

    print("Thank you for using Turtle paint.")

def move():
    wn.mainloop()
    print("Turtle is facing 'RIGHT'.")
    while True:
        
        try:                # to eliminate unnecessarily errors from popping up
            q = input("Turn or move forward?\nturn/forward> ")      # turn or move forward prompt
            
            # based on the answer take input of degree and forward movement length
            if q.lower() == "turn":
                turn = input("Turn 'Right' or 'Left'?")
                degree = int(input(f"Turn {turn} by how much degree"))
                if turn.lower() == 'right':
                    tur.right(degree)
                elif turn.lower() =='left':
                    tur.left(degree)
            
            elif q.lower() == 'forward':
                movement = int(input("How much forward? type in number\n> "))
                tur.forward(movement)
        
        except:
            print('Turtle didnt catch that, try again!')
        
        # if the user want to continue or not
        # there is semantic error probably
        print("Wanna continue?")
            ans = input('> ')       
            if ans in ['yes', 'Yes', "YES", 'Y' ,'y']:
                pass
            else:
                break

if __name__ == '__main__':
    main()

Answer 1

尝试这样的事情：

#----------------
# turtle paint
#----------------

import turtle
from threading import Thread


def main():
    global wn, tur

    wn = turtle.Screen()
    tur = turtle.Turtle()

    move()

def move_asker():
    print("Turtle is facing \"RIGHT\".")
    while True:
        try:
            q = input("Turn or move forward?\nturn/forward/exit> ")

            if q.lower() == "turn":
                turn = input("Turn right or left? ")
                degree = int(input(f"Turn {turn} by how much degree"))
                if turn.lower() == "right":
                    tur.right(degree)
                elif turn.lower() == "left":
                    tur.left(degree)

            elif q.lower() == "forward":
                movement = int(input("How much forward? type in number\n> "))
                tur.forward(movement)

            elif q.lower() == "exit":
                wn.destroy()
                break

        except RuntimeError:
            # The user might have closed the window
            break

        except Exception as error:
            print("Error = " + repr(error))
            print("Turtle didnt catch that, try again!")

def move():
    thread = Thread(target=move_asker, daemon=True)
    thread.start()
    wn.mainloop()

if __name__ == "__main__":
    main()

在move function 中，它告诉 python 开始执行move_asker()并继续执行wn.mainloop() 。

然而，这种方法存在问题。 其中之一是， turtle可能会崩溃，甚至不会给你一个错误。 这就是为什么不建议将turtle与线程一起使用的原因。 我现在测试了程序中的所有命令，它们应该可以工作。

如果您从使用turtle切换并使用tkinter类的东西会更好（ turtle构建在tkinter之上，所以它不应该那么难）。 如果这样做，则使用Entry而不是使用input(...) 。 它将解决上述问题。