如何修复这个 bash 脚本？

Question

我在这里有这个脚本：

killall -q $1
#turns out system already has a method for this, yey
#-q because we already have a error handling
returned=$?
#does this so that it doesn't read the success state of the ifs
if [ $returned = 0 ]
then 
    printf "Process kill attempt returned "
    echo $returned
    echo "Process killed sucessfully."
    #yey we did it
else
    #oh noes it failed
    printf "Process kill attempt returned "
    echo $returned
    echo "Process kill attempt failed."
    printf "Most likely cause of failure: "
    if [ $returned = 1 ]
    then
        echo "process does not exist or is not running"
    elif [ $returned = 2 ]
        echo "process is system task; insufficient permissions"
    else
        echo "unknown failure " $returned "; no known fail in database has this value"
    fi
fi

查看它时，我认为没有问题，但是在运行时，出现此错误。

nathan@HAL-LINUX:~$ xscreensaver
nathan@HAL-LINUX:~$ killproc xscreensaver
/usr/local/bin/killproc: line 23: syntax error near unexpected token `else'
/usr/local/bin/killproc: line 23: ` else'
nathan@HAL-LINUX:~$ 

我的原始脚本省略了嵌套的 if，直接告诉你它失败了，错误 3 或 1 或 2。

我应该回去吗？ 或者有没有办法解决这个问题？

Answer 1

你忘记了你的elif之后的then ：

if [ $returned = 1 ]
    then
        echo "process does not exist or is not running"
    elif [ $returned = 2 ]
    then
        echo "process is system task; insufficient permissions"
    else
        echo "unknown failure " $returned "; no known fail in database has this value"
    fi