[英]How does the C compiler know memory location even though the program gets loaded in memory after the compilation phase? [duplicate]
一般来说，程序有编译和运行两个阶段。
编译时 - 编译器生成这样的源程序汇编 -
MOV R1 R2
负载 R2 1000
运行时 - 程序被加载到内存并开始执行。
问题： - 即使程序在编译阶段后被加载到内存中，编译器如何知道上述加载指令中的内存位置（例如 1000）？
在这个C程序中，静态变量的内存位置如何变化？
[英]How does the location in memory of a static variable change in this C program?
在 C 程序中读取 memory 时编译器的行为如何？ 这是我为理解而编写的以下代码：
[英]How does a compiler behave while reading memory in C program ? This is the following code I wrote to understand :
是否可以用C编写不执行任何操作-甚至不占用内存的程序？
[英]Is it possible to write a program in C that does nothing - not even taking up memory?
即使分配了内存，用于修改链表的C程序也会导致分段错误
[英]C Program for modifying linked list causes segmentation fault even though memory is allocated
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