为什么我的代码忽略了我的刽子手游戏的 if 语句？ （Python）

Question

我只是有一个关于我在下面写的代码的问题。 我只是想知道我用“if guess not in secret_word:”写的 if 语句。 当我按照当前编写的方式运行它时，条件甚至不会运行或出现。 但是，当我将它与我上面写的 for 语句交换时，它运行得很好。 我对编程有点陌生，我只是想知道是否有人可以帮助我解决这个问题。 为什么条件的顺序在这里很重要？

'''

import random
from words import words

secret_word = random.choice(words)
secret_letters = list(secret_word)
blanks = " _ " * len(secret_word)
already_guessed = []
lives = 10

print(blanks)


def valid_guess(): # function to make sure the letter guessed is valid (ie, not previously guessed)
    is_letter = True
    lives = 10

    while True:
        guess = (input("\nGuess a letter:"))

        if guess in already_guessed:
            print("You have already guessed this letter")
        elif len(guess) != 1:
            print("Please guess a single letter:")
            is_letter = False
        elif guess not in "abcdefghijklmnopqrstuvwxyz":
            print("Please guess a LETTER:")
            is_letter = False

        if is_letter:
            already_guessed.append(guess)

        for guess in secret_word:
            if guess in already_guessed:
                print(guess + " ", end = "")
            else:
                print(" - ", end = "")

        if guess not in secret_word:
            lives -= 1
            print(f"You lost a life! You only have {lives}/10 left!")


while True:
    valid_guess()

'''

Answer 1

你可以试试这个：

if guess in secret_word:
       if guess in already_guessed:
            print(guess + " ", end = "")
       else:
            print(" - ", end = "")

 elif guess not in secret_word:
       lives -= 1
       print(f"You lost a life! You only have {lives}/10 left!")