将格式化的数据库查询从 MySQL 转换为 MySQLi

Question

我在将格式化的 DB 查询从 MySQL 转换为 MySQLi 时遇到问题。 在 MySQL 中，以下代码生成了一个格式化列表，其中每一行形成一个格式良好的条目，所有这些都列在彼此的下方。 三个按钮将触发不同数据集的三个不同的数据库查询。 在 MySQLi 上，此代码现在生成一个连续的数据流，根本没有任何换行符或分段符。 有人可以帮助我了解如何恢复格式吗？

我应该补充一点，我是一个对 MySQLi 知之甚少的菜鸟程序员。 非常感谢！

<?php

include 'tools/config.php';
include 'tools/opendb.php';

if(isset($_POST['button1'])){

echo "



";

$link = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname);
$query = "SELECT title, type, publication, date, pub_desc, link FROM publications WHERE status=\"P\" ORDER BY date DESC";
$result = mysqli_query($link, $query);

while($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
echo "

{$row['title']} " .
"

{$row['pub_desc']}
" .
"{$row['publication']}, " .
"{$row['date']}, " .
"{$row['type']}


" ;
}

include 'tools/closedb.php';

}//if isset

if(isset($_POST['button3'])){

echo "



";

$query = "SELECT date, title, location, event FROM speeches ORDER BY date DESC";
$result = mysqli_query($link, $query);

while($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
echo "

" . $row['title'] . "
";
echo "

" . $row['event'] . ", " . $row['location'] . "
";
echo "

" . date( "M Y", strtotime($row['date'])) . "
";
echo "
";
}

include 'tools/closedb.php';

}//if isset

if(isset($_POST['button4'])){

echo "



";

$query = "SELECT title, type, date, event, location, organizer FROM seminars ORDER BY date DESC";
$result = mysqli_query($link, $query);

while($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
echo "

" . $row['title'] . "
";
echo "

" . $row['event'] . ", " . $row['organizer'] . "
";
echo "

" . $row['location'] . ", " . date( "M Y", strtotime($row['date'])) . "
";
echo "
";
}

include 'tools/closedb.php';

}//if isset

?>

Answer 1

由于输出显示在网络浏览器中，因此我假设您要echo的文档是 HTML 格式的。
因此，您是否尝试过将echo的新行替换为<br> ？