如何通过在 python 中进行批处理来获取唯一的元组

Question

{'45': 1,
 '24': 9,
 '15': 9,
 '23': 7,
 '9': 5,
 '40': 7,
 '94': 8,
 '59': 7,
 '48': 4,
 '1': 7,
 '80': 9,
 '77': 0,
 '2': 1,
 '28': 1,
 '87': 1,
 '44': 5,
 '84': 5,
 '35': 4,
 '21': 9,
 '27': 9,
 '66': 7,
 '8': 9,
 '19': 8,
 '36': 4,
 '56': 8,
 '58': 1,
 '76': 5,
 '60': 9,
 '85': 2,
 '54': 7,
 '30': 2,
 '7': 9,
 '38': 0,
 '98': 1,
 '25': 1,
 '82': 1,
 '95': 4,
 '62': 6,
 '99': 1,
 '17': 7,
 '31': 8,
 '57': 5,
 '72': 0,
 '53': 5,
 '69': 0,
 '63': 5,
 '18': 7,
 '88': 4,
 '67': 9,
 '55': 8,
 '74': 6,
 '12': 0,
 '71': 4,
 '81': 5,
 '13': 8,
 '83': 4,
 '5': 7,
 '47': 4,
 '22': 1,
 '51': 4,
 '96': 2,
 '49': 6,
 '14': 6,
 '79': 8,
 '61': 0,
 '78': 6,
 '39': 2,
 '0': 4,
 '34': 7,
 '90': 3,
 '68': 0,
 '4': 4,
 '10': 3,
 '70': 8,
 '93': 3,
 '89': 1,
 '6': 5,
 '75': 7,
 '32': 2,
 '29': 2,
 '33': 8,
 '52': 7,
 '91': 7,
 '46': 1,
 '20': 3,
 '42': 9,
 '50': 3,
 '37': 2,
 '97': 0,
 '64': 1,
 '73': 6,
 '43': 1,
 '26': 3,
 '65': 1,
 '3': 0,
 '16': 0,
 '11': 9,
 '86': 7,
 '92': 5,
 '41': 9}

排序后

[('77', 0),
 ('38', 0),
 ('72', 0),
 ('69', 0),
 ('12', 0),
 ('61', 0),
 ('68', 0),
 ('97', 0),
 ('3', 0),
 ('16', 0),
 ('45', 1),
 ('2', 1),
 ('28', 1),
 ('87', 1),
 ('58', 1),
 ('98', 1),
 ('25', 1),
 ('82', 1),
 ('99', 1),
 ('22', 1),
 ('89', 1),
 ('46', 1),
 ('64', 1),
 ('43', 1),
 ('65', 1),
 ('85', 2),
 ('30', 2),
 ('96', 2),
 ('39', 2),
 ('32', 2),
 ('29', 2),
 ('37', 2),
 ('90', 3),
 ('10', 3),
 ('93', 3),
 ('20', 3),
 ('50', 3),
 ('26', 3),
 ('48', 4),
 ('35', 4),
 ('36', 4),
 ('95', 4),
 ('88', 4),
 ('71', 4),
 ('83', 4),
 ('47', 4),
 ('51', 4),
 ('0', 4),
 ('4', 4),
 ('9', 5),
 ('44', 5),
 ('84', 5),
 ('76', 5),
 ('57', 5),
 ('53', 5),
 ('63', 5),
 ('81', 5),
 ('6', 5),
 ('92', 5),
 ('62', 6),
 ('74', 6),
 ('49', 6),
 ('14', 6),
 ('78', 6),
 ('73', 6),
 ('23', 7),
 ('40', 7),
 ('59', 7),
 ('1', 7),
 ('66', 7),
 ('54', 7),
 ('17', 7),
 ('18', 7),
 ('5', 7),
 ('34', 7),
 ('75', 7),
 ('52', 7),
 ('91', 7),
 ('86', 7),
 ('94', 8),
 ('19', 8),
 ('56', 8),
 ('31', 8),
 ('55', 8),
 ('13', 8),
 ('79', 8),
 ('70', 8),
 ('33', 8),
 ('24', 9),
 ('15', 9),
 ('80', 9),
 ('21', 9),
 ('27', 9),
 ('8', 9),
 ('60', 9),
 ('7', 9),
 ('67', 9),
 ('42', 9),
 ('11', 9),
 ('41', 9)]

假设我想做分块（做 10 个批次），所以我想返回 10 对，每对应该只有一次值。

如果我们想做 30 的批处理，那么我们可以重复，因为我们没有足够的唯一值。

基本上，我想手动创建一个批处理方法（我们在 Keras 中使用）。

我试过这个 - ： Python：获取唯一元组，使得所有元组中的元素不相交，这不起作用。

我可以使用以下方法进行简单的批处理，但情况并非如此

For loop: list[i:i+batch_size]

提前致谢。