Node.js 避免同时写入损坏文件内容

Question

此代码导致针对同一个文件指针同时执行一堆写操作（具有相对较大的有效负载）：

(async () => {
  
  let fs = require('fs').promises;
  let file = '/junk.txt';
  
  await fs.writeFile(file, '');
  
  let payloads = [
    'abc'.repeat(500 * 1000),
    'def'.repeat(500 * 1000),
    'ghi'.repeat(500 * 1000),
    'jkl'.repeat(500 * 1000),
    'mno'.repeat(500 * 1000),
    'pqr'.repeat(500 * 1000)
  ];
  
  // Write every payload to the same file at the same time
  await Promise.all(payloads.map(p => fs.writeFile(file, p)));
  
  // Detect if the payload is corrupted; i.e. it is a mashed up version
  // of multiple payloads
  let result = await fs.readFile(file, 'utf8');
  if (!payloads.includes(result)) console.log('UNEXPECTED CONTENT:', content);
  
})();

对我来说，“意外内容”消息可靠地出现，表明文件的内容是多个不同有效负载的产物； 即，它的内容是“损坏的”。

我可以使用什么技术来确保文件的内容永远不会损坏？ 我是否需要在全局级别为每个唯一文件句柄维护一个待处理的文件操作队列，例如require('fs').promises.writeFile这种装饰？

// Global map of file handle -> queue of operations on that handle
let busyFiles = Map();

let fs = require('fs').promises;
let origWrite = fs.writeFile;

fs.writeFile = (handle, ...args) => {
  
  // Wait for any globally registered writes on `handle` to complete
  // before performing the requested write operation
  
  if (!busyFiles.has(handle)) busyFiles.set(handle, Promise.resolve());
  
  let prm = busyFiles.get(handle)
    .then(() => origWrite.call(fs, handle, ...args);
  
  // Register this write operation in the global queue
  busyFiles.set(handle, prm);
  
  return prm;
  
};

还是有更聪明的方法？ （例如，在文件不再进行写入操作时查询操作系统以获取通知 - 这也可以防止多个 node.js 实例并行运行时损坏）