ProjectTo<DTO> 支持 Flattening 吗？

Question

代码

 _doctorRepository.Find(t => t.Id == doctorId).ProjectTo<EmploymentDTO>(_mapper.ConfigurationProvider).FirstOrDefault()

映射配置

            // doctor have  Navigation property Hospital
            CreateMap<Doctor, EmploymentDTO>().IncludeMembers(t => t.Hospital);                
            CreateMap<Hospital, EmploymentDTO>();

预期行为

SELECT TOP(1) [d].[Id], [d].[DepartmentId], [d].[DepartmentOther], [d].[DepartmentOtherCN], [d].[HospitalId], [d].[PositionId], [d].[PositionOther], [d].[PositionOtherCN], [d].[RankId], [d].[RankOther], [d].[RankOtherCN], [h].[City], [h].[Country], [h].[UniversityAffiliated], [h].[HospitalName], [h].[Province], [h].[CityCN], [h].[CountryCN], [h].[UniversityAffiliatedCN], [h].[HospitalNameCN], [h].[ProvinceCN]
FROM [Doctor] AS [d] WITH (NOLOCK)
LEFT JOIN [Hospital] AS [h] WITH (NOLOCK) ON [d].[HospitalId] = [h].[Id]
WHERE [d].[Id] = @__doctorId_0

实际行为：

未离开加入医院表

SELECT TOP(1) [d].[DepartmentId], [d].[DepartmentOther], [d].[DepartmentOtherCN], [d].[HospitalId], [d].[Id], [d].[PositionId], [d].[PositionOther], [d].[PositionOtherCN], [d].[RankId], [d].[RankOther], [d].[RankOtherCN]
FROM [Doctor] AS [d] WITH (NOLOCK)
WHERE [d].[Id] = @__doctorId_0