线程 1：EXC_BAD_ACCESS C++/Xcode

Question

我创建了一个航空公司预订系统，并在主目录中创建了一个 Customer* Ptr[100] 以指向客户 Object。 我的客户 Object 有一个经济舱 object，它本身继承自抽象票证 Class。 我运行该程序并创建一个所有信息都没有问题的客户，但是当我想查找一张票以从中获取信息时给了我这个错误。 BAD ACCESS AT ( Ptr[i]->E1.getTicketNumber ) - 让我知道更多代码

int tChoice;
        cout<<"====================================================="<<endl;
        cout<<"Please select the type of ticket that you want to get: "<<endl;
        cout<<"1. Ecnomoy Ticket."<<endl;
        cout<<"2. Bussines Ticket."<<endl;
        cout<<"3. First Class Ticket."<<endl;
        cin >> tChoice;
        while (tChoice != 1 && tChoice !=2 && tChoice !=3) {
            cout<<"INVALID SELECTION - Please enter one of the above: "<<endl;
            cin >> tChoice;
        }
        switch (tChoice) {
            case 1:
                Ptr[i] = new Customer;
                Ptr[i]->setName();
                Ptr[i]->setLastName();
                Ptr[i]->setAddress();
                Ptr[i]->setPhoneNumber();
                Ptr[i]->setRewards();
                Ptr[i]->setPosition(i);
                Ptr[i]->E1.setDeparture();
                Ptr[i]->E1.setSeatNumber();
                Ptr[i]->E1.setDestination();
                Ptr[i]->E1.setTicketNumber();
                Ptr[i]->E1.setTime();
                Ptr[i]->E1.setMiles();
                Ptr[i]->E1.setRate();
                Ptr[i]->setRewards();
                Ptr[i]->showRewards();
                i++;
                break;

--------      SOME CODE.     ---------

                  case 'B':
        case 'b': {
            int j = 0;
            cout<<"Please enter the flight class and ticket number to cancel: "<<endl;
            cout<<"1. Ecnomomy Class"<<endl;
            cout<<"2. Bussines Class"<<endl;
            cout<<"3. First Class"<<endl;
            cin >> j;
            while (j != 1 && j !=2 && j !=3) {
                cout<<"INVALID SELECTION - Please enter one of the above unmbers: "<<endl;
                cin >> j;
            }
            switch (j)
            {
                case 1: {
                    int num = 0;
                    cout<<"Please enter the ticket number: "<<endl;
                    cin >> num;
                    for ( int i= 0 ; i < 100 ; i++)
                    {
                        if ( num == Ptr[i]->E1.getTicketNumber()) =====> BAD ACCESS HERE
                        {
                            Ptr[i]->E1.canceling();
                        }
                    }
                    
                    break;
                }